Sqare √113
113
10^2=100, so √100=10
11^2=121 so √121=11
√100<√113<√121
so therfor
10<√113<11
it is between 10 and 11
Answer:
<h2>PLEASE MARK BRAINLIEST!!</h2>
Yes
Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.
This number is natural, whole, integer, and rational.
Whole numbers are numbers such as 0, 1, 2, ... This is a whole number.
Natural numbers can also be counting numbers. They are the whole numbers, but starting at 1, not 0. This is a natural number.
Integers are whole numbers with negatives. This is an integer.
Rational numbers are any numbers that can be written as a fraction. We can write this as 4563/1, so it is rational.
Answer:
the photo is a little blurry I cannot answer the question unfortunately sorry
