An easy way to do this is to parameterize the directed line segment from B to A by the function
with 0 ≤ t ≤ 1.
The point P₂ splits up AB so that BP₂ = 3/8 AB and AP₂ = 5/8 AB. Then we reach the point P₂ when t = 3/8, so its coordinates are
Answer:
Step-by-step explanation:
I think that the answer is a because you only have to terms after you distribute hope this helps you
Answer:
The longest side length b is approximately 13.172 cm
Step-by-step explanation:
The given parameters are;
The area of the triangle = 22.4 cm²
The given angles of the triangle = ∠97°
The given side of the triangle = 3.7 cm
The formula for the area of a triangle, A = 1/2 × a × b × sin(C)
Where;
a, and b are the side legs forming the angle C
Therefore, we have;
A = 22.4 = 1/2 × 3.7 × a × sin(97°)
a = 22.4/(1/2 × 3.7 × sin(97°)) ≈ 12.199
a ≈ 12.199 cm
Therefore, by cosine rule, we have;
b² = a² + c² - 2 × a × c × Cos(B)
Substituting the values, gives;
b² = 12.199² + 3.7² - 2 × 12.199 × 3.7 × Cos(97°)
b² ≈ 173.507
∴ b ≈ √173.507 ≈ 13.172
b ≈ 13.172 cm
(x + 7)/2 - (x + 4)/2 = (x + 7 - (x + 4)/2 = (x + 7 - x - 4)/2 = 3/2
