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Anna35 [415]
3 years ago
8

The product of 9 and t squared, increased by the sum of the square of t and 2

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

9t^2+(t+2)^2

Step-by-Step:

t is 9 X t, or the product of 9 and t. ^2 is squared while + is increased t+2 is the sum of t and t. the ^2 after the parenthesis is indicating the "square of t and 2"

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Round this whole number Round 10,652 to the nearest ten.
ValentinkaMS [17]

Answer:

10650

Step-by-step explanation:

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Is this a A.M or P.M activity? Thank you in advance.
Margarita [4]
This is an A.M. activity because normally, you would go to classes during the morning.
Hope this helps!
3 0
3 years ago
Randi shovels and salts her neighbors' driveways and walkways to earn money during the winter months in her town near the Pocono
grin007 [14]

Answer:

25t = 65

Step-by-step explanation:

Given that :

Profit earned = $60

Charge per hour = $25

Randy's cost or expenses = $(2 + 3) = $5 per job

Profit = (charge per hour * t) - cost

Where t = time

$60 = ($25 * t) - $5

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7 0
3 years ago
Please help, i’ve been in apex and i don’t know what the answer is
Marizza181 [45]

Answer:

A

Step-by-step explanation:

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3 0
3 years ago
Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
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