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3 years ago

Find the percentage increase from 360km to 540km

Mathematics

1 answer:

vodomira [7]3 years ago

6 0

Answer: 66 2/3

Step-by-step explanation:

360 x

—— = ——

540 100

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larisa86 [58]

Distance formula

$\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

Now

$\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units$

$\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units$

$\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units$

$\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units$

$\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units$

8 0

2 years ago

Read 2 more answers

The degree of the polynomial x+y^2-7xy-6w^kz^2 is 10. What is the value of k?

Alenkasestr [34]

The value of k is 8 hope i was helpful

3 0

3 years ago

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In 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B. If 70 houses wer

Stella [2.4K]

Answer:

The number of houses built in Town B is 56.

Step-by-step explanation:

We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.

Also, 70 houses were built in Town A during 210.

Let the number of houses built in Town B be 'x'.

So, according to the question;

Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B

$70 = x + (25\% \times x)$

$70 = x(1+0.25)$

$x=\frac{70}{1.25}$

x = 56

Hence, the number of houses built in Town B is 56.

8 0

3 years ago

HELP ME PLEASE ON THIS

Anvisha [2.4K]

The answer is [ all real numbers ]

The domain are the input values which makes the function defined and real.

Since we don't have any constraints or any undefined points, the domain could be literally anything. Thus proves out answer.

Best of Luck!

5 0

3 years ago

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LESSON

bagirrra123 [75]

C is the answer hope that helps have a good day

5 0

3 years ago