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agasfer [191]
3 years ago
9

Jason is trying to prove that this quadrilateral is a rhombus. Using the slope formula, he finds that opposite sides of the poly

gon are parallel. Since all of the sides appear to be congruent, Jason concludes that ABCD is a rhombus. Is Jason's reasoning correct? Why or why not
Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

No, it is not.

Step-by-step explanation:

Proving the opposite sides are parallel is the correct first step.  If the quadrilateral is not a parallelogram, it cannot be a rhombus.

After knowing the quadrilateral is a parallelogram, we must know whether the sides are congruent.  To do this, we must use the distance formula to find the length of each side.

Hunter-Best [27]3 years ago
4 0
Opposite sides being parallel proves that hte figure is a parallelogram.  The sides only appear to be equal so his conclusion is not valid. He would need to show that  2 adjacent sides of the parallelogram are equal ( using the distance formula)  to prove that it is a rhombus.
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Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d
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Question not well presented

Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

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The numerical length of RS is 22

Step-by-step explanation:

Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

4x - 4 = 4x - 10 + 2x - 10 --- collect like terms

4x - 4 = 4x + 2x - 10 - 10

4x - 4 = 6x - 20--- collect like terms

6x - 4x = 20 - 4

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x = 8

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Hence, the numerical length of RS is calculated as 22

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