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agasfer [191]
3 years ago
9

Jason is trying to prove that this quadrilateral is a rhombus. Using the slope formula, he finds that opposite sides of the poly

gon are parallel. Since all of the sides appear to be congruent, Jason concludes that ABCD is a rhombus. Is Jason's reasoning correct? Why or why not
Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

No, it is not.

Step-by-step explanation:

Proving the opposite sides are parallel is the correct first step.  If the quadrilateral is not a parallelogram, it cannot be a rhombus.

After knowing the quadrilateral is a parallelogram, we must know whether the sides are congruent.  To do this, we must use the distance formula to find the length of each side.

Hunter-Best [27]3 years ago
4 0
Opposite sides being parallel proves that hte figure is a parallelogram.  The sides only appear to be equal so his conclusion is not valid. He would need to show that  2 adjacent sides of the parallelogram are equal ( using the distance formula)  to prove that it is a rhombus.
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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

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This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

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Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

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5 0
3 years ago
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AlladinOne [14]

Answer:

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Step-by-step explanation:

Substitute the second equation into the first, replacing y in the first:

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Simplifying, we get:

2x + 4x - 2 = 10, or:

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Substituting 2 for x in the second equation yields y = -4(2) + 2 = 0, or y = -6

Then the solution is (2, -6).

5 0
2 years ago
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irina1246 [14]

Answer:

3.7

Step-by-step explanation:

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a_sh-v [17]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices that can be found from other source:

A.$340 
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