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levacccp [35]
4 years ago
15

Simplify cos5cos40-sin5cos40

Mathematics
2 answers:
worty [1.4K]4 years ago
8 0
<span>= sin(40+50)
= sin 90
= 1
</span>
galben [10]4 years ago
3 0

Answer:

cos(5)cos(40) - sin(5)cos(40) = cos(45) = √(2)/2

Step-by-step explanation:

One of the trig identity (Angle Sum/Difference Identity) is:

cos(α + β) = cos(α) cos(β) – sin(α) sin(β)

We're given: cos(5)cos(40) - sin(5)cos(40)

In this case, α=5 and β=40

Plug it into you're equation

cos(α + β) = cos(α) cos(β) – sin(α) sin(β)

cos(5 + 40) = cos(5)cos(40) - sin(5)cos(40)

cos(5 + 40) = cos(45) = √(2)/2

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Find the base of the triangle whose area is 2.4 cm² and who is height is 1.6 cm
Karo-lina-s [1.5K]

Formula of the area of triangle: (BxH)/2

So:

1.6B/2 = 2.4

Multiply both sides by 2:

1.6B = 4.8

Divide both sides by 1.6:

B = 3

6 0
4 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Elenna [48]

Answer:

cos(V)=\frac{39}{89}=.44

∠V=64.01°

Step-by-step explanation:

sin(angle)=\frac{opposite}{hypotenuse}

cos(angle)=\frac{adjacent}{hypotenuse}

tan(angle)=\frac{opposite}{adjacent}

  • The cosine of an angle is equal to the side adjacent to the angle over the hypotenuse, the longest side.
  • With this in mind:

cos(V)=\frac{39}{hypotenuse}

  • We need to find the hypotenuse of this triangle. This is relativly easy to do with a right triangle; we can just use the Pythagorean Theorem.
  • Pythagorean Theorem: a^2+b^2=c^2  where a, b, and c are the 3 different sides of a right triangle.

a^2+b^2=c^2\\(39)^2+(80)^2=c^2\\1521+6400=c^2\\c=\sqrt{7921} \\c=89

  • Our hypotenuse is 89. Now we can finish solving for ∠V.

cos(V)=\frac{39}{89}\\V=cos^-^1(\frac{39}{89})\\

∠V=64.01°

3 0
4 years ago
The hypotenuse of a right triangle is 26m and the sum of its legs is 34m. Find the legs.
marysya [2.9K]

Answer: If you need to find the length of the hypotenuse of a right triangle, you can use the Pythagorean theorem if you know the length of the other two sides. Square the length of the 2 sides, called a and b, then add them together. Take the square root of the result to get the hypotenuse

6 0
3 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
What is the m∠B? Please help this is due soon.
Art [367]

Answer:

add all given angle

sum of all angles is equal to 180 degree

5 0
3 years ago
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