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3 years ago

Estimate the equation 12+ 19.61

Mathematics

2 answers:

Mandarinka [93]3 years ago

4 0

QUESTION:

QUESTION:estimate the equation 12+19.61.

QUESTION:estimate the equation 12+19.61.Answer:

QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.

Anuta_ua [19.1K]3 years ago

3 0

12 + 19.61
Usually we round off the number when we do estimates
12 + 20 = 32

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What is bigger 1/5 or .29

n200080 [17]

.29 is bigger.

If you convert 1/5 to a decimal (or simply solve it!) you will end up with .2 or .20
Which is obviously smaller than .29

3 0

3 years ago

Read 2 more answers

The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?

VARVARA [1.3K]

Answer:

$\displaystyle - 155$

Step-by-step explanation:

we are given a quadratic function

$\displaystyle f(x) = - 5 {x}^{2} + 30x - 200$

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

$\displaystyle x _{ \rm min} = \frac{ - b}{2a}$

the given function is in the standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

so we acquire:

b=30
a=-5

thus substitute:

$\displaystyle x _{ \rm min} = \frac{ - 30}{2. - 5}$

simplify multiplication:

$\displaystyle x _{ \rm min} = \frac{ - 30}{ - 10}$

simply division:

$\displaystyle x _{ \rm min} = 3$

plug in the value of minimum x to the given function:

$\displaystyle f (3)= - 5 {(3)}^{2} + 30.3 - 200$

simplify square:

$\displaystyle f (3)= - 5 {(9)}^{} + 30.3 - 200$

simplify multiplication:

$\displaystyle f (3)= - 45 + 90- 200$

simplify:

$\displaystyle f (3)= - 155$

hence,

the minimum value of the function is -155

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2 years ago

Ed and Greg are working on their math homework. Ed says (2.0) is a solution to y < 4x - 8. Greg disagrees and says (2,0) is n

Tom [10]

Answer:

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Step-by-step explanation:

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3 years ago

Find a polynomial f(x) of degree 3 that has the following zeros.

Thepotemich [5.8K]

Answer:

$f (x) = x (x + 5) (x-9)$

Step-by-step explanation:

The zeros of the polynomial are all the values of x for which the function $f (x) = 0$

In this case we know that the zeros are:

$x = 9,\ x-9 =0$

$x = 0$

$x = -5$ , $x + 5 = 0$

Now we can write the polynomial as a product of its factors

$f (x) = x (x + 5) (x-9)$

Note that the polynomial is of degree 3 because the greatest exponent of the variable x that results from multiplying the factors of f (x) is 3

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3 years ago

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3 years ago