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sp2606 [1]
3 years ago
10

Estimate the equation 12+ 19.61

Mathematics
2 answers:
Mandarinka [93]3 years ago
4 0

<em>QUESTION:</em>

<em>QUESTION:estimate the equation 12+19.61.</em>

<em>QUESTION:estimate the equation 12+19.61.Answer:</em>

<em>QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.</em>

Anuta_ua [19.1K]3 years ago
3 0
12 + 19.61
Usually we round off the number when we do estimates
12 + 20 = 32
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Tina left for school at 8:35 a.m. and she got back home at 3:45 p.m. How long was
a_sh-v [17]

Answer:

430 minutes or 7 hours and 10 minutes

Step-by-step explanation:

From 8:35 am to 9 am is 25 minutes. There are 60 minutes in an hour and 9 am to 3 pm is 6 hours. 3:00 to 3:45 pm is an additional 45 minutes.

60 minutes x 6 hours = 360 minutes

360 + 25 + 45 = 430 minutes

3 0
3 years ago
Read 2 more answers
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Someone help asap please, thanks!
Sever21 [200]
Graph B is the correct answer
7 0
3 years ago
A sports shop has 30 employees. 70% of the employees work part-time. How many part-time employees does the sports shop have?
noname [10]

Answer:

21

Step-by-step explanation:

all you have to do is get 70% of 30

70% of 30 is 21

4 0
2 years ago
Read 2 more answers
I need some help with math
Irina18 [472]

Answer:

(y-7)^2+(x-2)^2=16

and

(x+2)^2+(y-15)^2 = 9

Step-by-step explanation:

The standard equation of a circle is (x-h)^2+(y-k)^2=r^2 where the coordinate (h,k) is the center of the circle.  

Second Problem:

  1. We can start with the second problem which uses this info very easily.
  2. (h,k) in this problem is (-2,15) simply plug these into the equation. (x--2)^2+(y-15)^2=r^2 .
  3. We can also add the radius 3 and square it so it becomes 9. The equation.
  4. This simplifies to (x+2)^2+(y-15)^2 = 9.

First Problem:

  1. The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
  2. y^2-14y+x^2-4x+37=0 first subtract 37 from both sides so the equation is now y^2-14y+x^2-4x=-37.
  3. y^2-14y+x^2-4x+37=0 by adding (-\frac{b}{2a} )^2 to both the x and y portions of this equation you can complete the squares. (-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2 and (-\frac{-4}{2(1)})^2 which equals 49 and 4.
  4. Add 49 and 4 to both sides and the equation is now:y^2-14y+49+x^2-4x+4=-37+49+4 You can simplify the y and x portions of the equations into the perfect squares or factored form (y-7)^2 and (x-2)^2.
  5. Finally put the whole thing together. (y-7)^2+(x-2)^2=16.

I hope this helps!

5 0
3 years ago
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