Answer:
Transitive
If x = 2y and 2y = 8, then x = 4.
We have that
<span>observing the graph of the problem, it is evident that the solution is option D, since the graph of the parabola presents a domain for x <4 and the line presents a domain for x> = 4 and the only option with these two conditions is option D
</span>
using a graph tool
<span>I proceed to verify</span>
see the attached figure
the answer is the option D
3 - 2x + 5 < -4(x + 2)
-2x + 8 < -4(x + 2)
-2x + 8 < -4x - 8
-2x + 8 + 4x < -8
2x + 8 < -8
2x < -8 - 8
2x < -16
x < -16/2
x < -8
Answer: A) x < -8
Given
centre of circle O(3,2)=O(x0,y0)
point on circle P(6,-2)
Standard equation of circle:
(x-x0)^2+(y-y0)^2=r^2
r=radius of circle
= (distance OP)
= sqrt((6-3)^2+(-2-2)^2)
=sqrt(3^2+(-4)^2)
=sqrt(25)
=>
r^2=(sqrt(25))^2=25
Equation of circle
(x-x0)^2+(y-y0)^2=r^2
(x-3)^2+(y-2)^2=25 ............... standard equation of circle
Answer:
exact form 77/8
decimal form 9.625
mixed number form 9 5/8