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4 years ago

ILLL MARK YOU BRAINLIEST

Mathematics

1 answer:

notka56 [123]4 years ago

5 0

Answer is the 3rd one

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Amanda had $20 when she went into the shopping center. She purchased a snack to eat for $y and then bought two items at a clothi

Volgvan

Answer:

x+y=20

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Need to evaluate 256 and fraction 1/4

postnew [5]

Answer:

256fraction=1/4

256÷4=64

64 answer this fraction

6 0

3 years ago

John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches.

Lady_Fox [76]

Answer:

13.5 inches

Step-by-step explanation:

Perimeter of the paper square = 18inches

Perimeter of a square = 4s

4s = 18 inches

s = 18/4 = 4.5 inches

Therefore, each side of the square = 4.5 inches.

When the square is cut into 2 rectangles,

The perimeter of one of the rectangles is 10 inches.

Perimeter of the second rectangle = 2L + 2W

Let the length of the rectangle (L) = one side of the square = 4.5 inches

Width of the Rectangle = Length of the square/2 = 4.5 inches/ 2 = 2.25

Perimeter of the second rectangle = 2(4.5) + 2(2.25)

= 9 + 4.5

= 13.5 inches

4 0

3 years ago

Part 1: What mistake did AJ make in the graph?

grigory [225]

Answer:

Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) see the explanation

Step-by-step explanation:

Part 1) What mistake did AJ make in the graph?

we have

$f(x)=-(x+2)^2-1$

This is the equation of a vertical parabola written in vertex form

The parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The vertex is the point (-2,-1)

therefore

AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?

take the values x=-4 and x=4

For x=-4

substitute the value of x in the quadratic equation

$f(x)=-(-4+2)^2-1\\f(x)=-5$

For x=4

substitute the value of x in the quadratic equation

$f(x)=-(4+2)^2-1\\f(x)=-37$

According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative

therefore

AJ made a mistake in the graph

8 0

3 years ago

Ok i know this is dum and I I'm highschool but my dad want me to do this

gregori [183]

Answer:

6 is the answer. Hope this helps.

6 0

3 years ago