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Solnce55 [7]
3 years ago
8

Help again...............​

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

h. 30, i. 42, j. 136

Step-by-step explanation:

Its really just basic math.

Maru [420]3 years ago
5 0
The answer to this would be

H. 30
I.48
J. 136
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A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (-4, 1), (1, 1), and (1, -11). What
Jlenok [28]
The answer is 30. hope it will help you.
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3 years ago
Exercise Plus charges a yearly fee of $75 plus $10 a month. Gym and Swim charges a yearly fee of $50 plus $15 a month. When , if
Natasha2012 [34]

Answer:

5 months will be the same cost at each gym.

Step-by-step explanation:

As

  • Exercise Plus charges a yearly fee of $75 plus $10 a month.
  • Gym and Swim charges a yearly fee of $50 plus $15 a month.

Let x by the number of months

75+10x=50+15x

10x=15x-25

-5x=-25

\frac{-5x}{-5}=\frac{-25}{-5}

x=5

Therefore, 5 months will be the same cost at each gym.

4 0
3 years ago
Write the slope intercept form of a line that passes<br> through (3, -2) and is 1 to y = x + 3.
zhuklara [117]

Answer:12

Step-by-step explanation:

8 0
4 years ago
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
Solve the initial value problem. 7y′−4y=e−πt2, y(0)=a Let a0 be the value of a for which the transition from one type of long-ru
densk [106]

Answer:

as shown in the attached file

Step-by-step explanation:

The detailed steps and application of differential equation, the use of integrating factor to generate the solution and to solve for the initial value problem is as shown in the attached file.

8 0
3 years ago
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