FInd three consecutive even integers such that three times the smallest is four more than twice the largest
1 answer:
n, n + 2, n + 4 - three consecutive even integers
3n = 2(n + 4) + 4 |use distributive property
3n = (2)(n) + (2)(4) + 4
3n = 2n + 8 + 4
3n = 2n + 12 |subtract 2n from both sides
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
Answer: 12, 14, 16.
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