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Margaret [11]
3 years ago
11

A sports club charges an initiation fee and a monthly fee. At the end of the 5 months, a member had paid a total of $450. At the

end of the 10 months, she had paid a total of $500.
a) Write a linear system to model the situation
b) Solve the linear system by substitution to solve the related problem: What are the initiation fee and the monthly fee?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:Initiation fee is $400 while monthly fee is $10

Step-by-step explanation:

Let the initial fee be x which is fixed while the monthly fee be y

At the end of 5 months, 450 was paid

This means that;

x + 5y = 450 ••••••••(i)

At the end of 10 months, $500 was paid

Mathematically, this means that;

x + 10y = 500•••••••••••(ii)

now we solve both equations simultaneously to get the value of x and y

our equation ii can be rewritten as;

x + 5y + 5y = 500

we can now insert equation i directly into this

450 + 5y = 500

5y = 500-450

5y = 50

y = 50/5

y = $10

From x + 5y = 450

let’s insert the calculated value of y

x + 5(10) = 450

x + 50 = 450

x = 450-50

x = $400

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If you do the math 2(5-3) exponent 2 - 4 = 4

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svetoff [14.1K]

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1) decay

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3) growth

Step-by-step explanation:

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Answer:

1. P(X≥35) = 0.0183

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3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

p=X/n=35/140=0.25

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239

We calculate the z-score as:

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Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

p=X/n=21/140=0.15

We can calculate then the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

P(X

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The sample size is n=300.

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We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

P=P(0.18

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