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Rom4ik [11]
3 years ago
14

0.00000000005 in scientific notation

Mathematics
1 answer:
marta [7]3 years ago
4 0

It can be written as 5 x 10^ -11 or 0.5 x 10^ -10

Hope it helps.

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Kyra is traveling to Canada and will exchange $250 into Canadian dollars. The current exchange rate of $1 US is equal to $1.03 C
Margaret [11]

Answer:

She will get $275.50 in return

Step-by-step explanation:

250 x 1.03 = 257.50

8 0
3 years ago
M+9n<br> m=7 n=6<br> hurryyyyyyyyyyyyyyyyyyyyyyyy
eduard
7 + 9 *6
7 + 54
61 - final answer
8 0
3 years ago
Read 2 more answers
Write y=1/6x+7 in standard form using integers
Law Incorporation [45]

The standard form using integers of the equation is 6y - x = 42

<h3>How to determine the standard form</h3>

Note that solving in standard form means writing it as a simple equation

Given y = 1/6x + 7

Find the LCM of the right side, we have

y = \frac{x + 42}{6}

Cross multiply

6 × y = x + 42

6y = x + 42

Make the variables move to the left side

6y - x = 42

Thus, the standard form using integers of the equation is 6y - x = 42

Learn more about algebraic expressions here:

brainly.com/question/723406

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8 0
2 years ago
The product of three whole numbers is 120 how many different possibilities are there for the three whole numbers
Sphinxa [80]
We can factor 120 into
2 * 2 * 2 * 3 * 5

I think there are nine different possibilities
1) 8 * 3 * 5
2) 4 * 2 * 15
3) 4 * 6 * 5
4) 4 * 10 * 3
5) 2 * 2 * 30
6) 2 * 3 * 20
7) 2 * 5 * 12
8) 2 * 6 * 10
9) 2 * 15 * 4



8 0
3 years ago
Read 2 more answers
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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