ANSWER: 7n-2
m-6n-3/m-13n-1
First you cross cancel m
then you get -6n-3/-13n-1
Thn you would subtract : 7n-2
<h3>I'll teach you how to solve 125 1/3</h3>
---------------------------------------------------
125 1/3
Convert mixed numbers to improper fractions:
125 1/3=
125*3+1/3=
376/3
Your Answer Is 376/3
plz mark me as brainliest :)
16 students turned in their homework early i think. I hope this helps
Answer:
-9
Step-by-step explanation:
x² -16 = (x -4)(x +4)
This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).
... For x-4 = ±1, x = 3 or 5
... For x+4 = ±1, x = -3 or -5
The values of x that are ±3 both give |x²-16| = 7, a prime.
The values of x that are ±5 both give |x²-16| = 9, not a prime.
The two values of x that are of interest are x=-3 and x=3. Their product is ...
... (-3)·(3) = -9
Answer:
An accountant
Step-by-step explanation:
Hope this helps, I don't have an explanation.
