Here is the problem.....√(15x + 10) = 2x+3
to remove the square root, we do the opposite which is to square everything.
(√(15x + 10))² = (2x + 3)² (the square negates the square root)
15x + 10 = (2x +3)(2x + 3) (use the distributive property to continue)
15x + 10 = 4x² + 6x + 6x + 9 (combine like terms)
15x + 10 = 4x² + 12x + 9 (subtract 15x and 10 from each side)
-15x - 10 -15x - 10
0 = 4x² - 3x - 1 (factor completely)
(x - 1) (4x + 1) (set each to equal 0)
x - 1 = 0 4x + 1 = 0
x = 1 4x = -1
x = -1/4
place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.
answer is 1
Answer:
x ≅ 7
Step-by-step explanation:
cos(67°) = x/18
x = 18cos(67°) ≅ 7
Answer:
<u><em>21 yard line</em></u>
Step-by-step explanation:
Ok we start out on the 20 yard line, we need to add the yards together.
<em>We add the 6 to the 20:</em>
20+6=26
<em>Then we subtract the 8 yards from our new 26:</em>
26-8=18
<em>Then we add the 18 by 3:</em>
18+3=21
Therefore,
<em>The Answer is 21 Yard Line.</em>
Hope I could help, If you need some more assistance ask me!
Answer:
It only counts as a zero when the y-intercept is (0,0).
Step-by-step explanation:
The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.
Umbilical
point.
An
umbilic point, likewise called just an umbilic, is a point on a surface at
which the arch is the same toward any path.
In
the differential geometry of surfaces in three measurements, umbilics or
umbilical focuses are focuses on a surface that are locally round. At such
focuses the ordinary ebbs and flows every which way are equivalent,
consequently, both primary ebbs and flows are equivalent, and each digression
vector is a chief heading. The name "umbilic" originates from the
Latin umbilicus - navel.
<span>Umbilic
focuses for the most part happen as confined focuses in the circular area of
the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces
with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an
outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two
umbilics.</span>
