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Leya [2.2K]
3 years ago
9

The Shady Farm Milk Company can process milk at a fixed rate of 7500 gallons/hour. The company’s clients request 100,000 gallons

of milk over the course of one day. This demand is spread out uniformly from 8 a.m. to 6 p.m. The company starts producing at 8 a.m. and continues to work until all of the demand has been satisfied. At noon, how many gallons of milk are in the queue to be processed?
Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

70000 gallons

Step-by-step explanation:

The total time between 8 a.m. to 6 p.m is 10 hours. The company starts producing at 8 am, therefore the time from 8 am to noon (that is 12 p.m) is 4 hours.

Since clients demand 100,000 gallons of milk over the course of one day, the demand of milk per hour = total demand per day/ total time per day

Demand per hour = 100000 gallons / 10 hours = 10000 gallons per hour

Since the milk is processed at a fixed rate of 7500 gallons/hour, At noon the amount of of milk produced = 7500 gallons/hour × 4 hours = 30000 gallons.

The gallons of milk are in the queue to be processed at noon = 100000 gallons - 30000 gallons = 70000 gallons

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A box contains three plain pencils and 5 pens. A second box contains three colored pencils and three crayons. One item from each
worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is \frac5{16}

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}

=\frac{5}{8}

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}

=\frac{3}{6}

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

=\frac58\times \frac36

=\frac5{16}

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4 0
3 years ago
Read 2 more answers
Can you please help me with this question
Luda [366]
So we are simply adding them

we will set the denominator equal by multiplying both the numerator and denominator
then just adding the numerator while keeping the denominator. look at my work. so your answer is 5/8

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