Answer:
1223.38 mmHg
Explanation:
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 
Also,
Moles = mass (m) / Molar mass (M)
Density (d) = Mass (m) / Volume (V)
So, the ideal gas equation can be written as:
Given that:-
d = 1.80 g/L
Temperature = 32 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (32 + 273.15) K = 305.15 K
Molar mass of nitrogen gas = 28 g/mol
Applying the equation as:
P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K
⇒P = 1223.38 mmHg
<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>
Answer:
108.3kPa
Explanation:
Given parameters:
Initial temperature = 76k
Initial pressure = 78.4kPa
Final temperature = 105k
Unknown:
Final or new pressure = ?
Solution:
To solve this problem, we apply the combined gas law:
= 
T1 = 76k
P1 = 78.4kPa
T2 = 105k
= 
P2 = 108.3atm
Answer:
Six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six
Explanation:
Hello there!
In this case, according to the molecular formula of the two moles of calcium phosphate:
Thus, in order to calculate the atoms of each atom, it is necessary to multiply the two in front of the formula by the subscripts in the reaction:
Thus, we obtain six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six.
Best regards!
Heat required : Q = 83500 J = 83.5 kJ
<h3>
Further explanation
</h3>
Given
mass ice = 250 g at 0°C
Required
The heat required
Solution
The heat to change the phase can be formulated :
Q = m.Lf (melting/freezing)
Lf=latent heat of fusion
Input the value :
Q = 250 g x 334 J/g
Q = 83500 J
