Question

A gas at 76 K is under a pressure of 78.4 kPa. If the temperature changes to 105 what will be the new

Answer 1

Answer:

108.3kPa

Explanation:

Given parameters:

Initial temperature  = 76k

Initial pressure  = 78.4kPa

Final temperature  = 105k

Unknown:

Final or new pressure  = ?

Solution:

To solve this problem, we apply the combined gas law:

           $\frac{P_{1} }{T_{1} }$     =    $\frac{P_{2} }{T_{2} }$

T1 = 76k

P1  = 78.4kPa

T2  = 105k

     $\frac{78.4}{76}$   = $\frac{P_{2} }{105}$  

     P2 = 108.3atm