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4 years ago

1025 divided by 5 long division

Mathematics

2 answers:

True [87]4 years ago

6 0

Answer:

205

Step-by-step explanation:

Lady_Fox [76]4 years ago

4 0

Answer:

205

Step-by-step explanation:

1025/5

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I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Savatey [412]

Answer:

f(x) = g(x-9)

Step-by-step explanation:

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3 years ago

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Please help!! giving brainlest , please be serious. due in a few minutes thanks!

Margaret [11]

The answer is -7

The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7

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3 years ago

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What is 3gh 2 x 4g 3h 3

Alexus [3.1K]

Answer:

(3•22g4h5)

Step-by-step explanation:

Step 1: ((3gh2 • 4) • g3) • h3

Step 2: ((3•22gh2) • g3) • h3

Step 3: 3.1 h2 multiplied by h3 = h(2 + 3) = h5

Final answer: (3•22g4h5)

(IF THIS HELPED PLEASE GIVE BRAINLIEST OR RATE IT 5 STARS!)

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3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

$n = 345$

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0

3 years ago

HURRY HELP! ILL MARK BRAINLEST ANSWER!!! if I have an 82 in a class, and I get 100 on two projects worth 15% of my grade, what w

dsp73

Answer:

Your final grade would be 87.4

Step-by-step explanation:

When an assessment is worth a certain percentage of a final grade, the grade percentage of the assessment is taken from its allocated percentage of the final grade. For example:

One project is worth 15% of the final grade, and you got 100% on it. This means that the percentage it contributes to the final grade is 100% (achieved) of 15% (allocated %). 100% of 15% is 15% (15x1). This means that if you hypothetically only completed the project 100% without other assessments, your final grade would be 15%.

This is the same for the other project: 100% (achieved) of 15 (% worth of final grade) = 15.

This is because when you get 100% on the project, you get the full 15% of its worth for the final grade (if that makes sense).

So, from both projects, the final grade would be 30.

Now for the 82.

Since the projects together are worth 30% of the final grade, it means that the 82 in class is worth the remaining 70%.

82% (achieved) of 70 (worth %) = 70x0.82 = 57.4

The 82 in class contributes 57.4 towards the final grade.

Since we have 30 from the projects, and the 57.4 from the class, your final grade would be 30+57.4 = 87.4

Hope this helped!

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4 years ago