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wariber [46]
3 years ago
10

Helppp Me will give brainliest to the first correct answer!!

Mathematics
2 answers:
Mariana [72]3 years ago
8 0

Answer: 62.4

Step-by-step explanation: just multiplied 2.6 x 3 x 8

IrinaK [193]3 years ago
6 0
62.4 because if you multiply 2.6 Times 8 times 3 that’s the answer you should get
You might be interested in
3. What is the equation in slope-intercept form of the line that passes through the
zavuch27 [327]
The Answer: y=1/4x+3
3 0
3 years ago
PLEASE HELP -7y + 11 = 75 + y
Masja [62]

Answer:

y = -8

Step-by-step explanation:

-7y + 11 = 75 + y

Bring the <em>"</em><em>y</em><em>"</em><em> </em>variable on one side, and rest on the other.

Rearranging, we get,

-7y - y = 75 - 11

-8y = 64

-y = 8

y = -8

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

3 0
3 years ago
Please help im so confused
MArishka [77]

Answer:

i

Step-by-step explanation:

i = \sqrt{-1}

i^2 = -1

i^3 = -i

i^4 = 1

(Make sure you know your exponent rules)

i^4^1 = i^4^0 * i = (i^1^0)^4 * i \\i^4 = 1 \\i^1^0 * i *1 \\i^1^0=1\\1*1*i=i

3 0
3 years ago
Need help with this one also
-Dominant- [34]

Answer:

D

Step-by-step explanation:

10/7 = 1.4285

9/y = 1.4285

Multiply both sides by y.

9 = 1.4285y

Divide both sides by y.

6.3 = y

6 0
3 years ago
Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\&#10;S_n=\cfrac{n(a_1+a_n)}{2}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;----------\\&#10;n=17\\&#10;S_{17}=-170\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}&#10;\\\\\\&#10;-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;n=17\\&#10;a_{17}=-22\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-22=2+(17-1)d\implies -22=2+16d\implies -24=16d&#10;\\\\\\&#10;\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
4 years ago
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