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Rashid [163]
3 years ago
8

Avery got on the bus at 1:25 P.M. The trip took 74 minutes. Then she walked for 61 minutes to get home.

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

3:40 p.m.

Step-by-step explanation:

Add 74 minutes to 1:25 p.m.; the improperly formed result witll be 1:99 p.m.; to express this properly, add 1 hour to this time and subtract 60 minutes from it:

2:39 p.m. (time at which Avery gets off the bus)

If Avery walked 61 minutes to get home and we want to know what time she arrived, we add 61 minutes to 2:39 p.m., obtaining 2:100 p.m., which must in turn be re-written as 3:40 p.m.

Avery arrived home at 3:40 p.m.

Note:  another way in which to do this problem is to add 74 minutes and 61 minutes, obtaining 135 minutes, and then adding 135 minutes to 1:25 p.m. and making the necessary adjustments to the result:

1:25 p.m. + 135 minutes = 1:160 p.m., or (recognizing that 120 min = 2 hours)

3:40 p.m.

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The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
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Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
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Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
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s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\&#10;s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\&#10;s= \frac{3(+-)\sqrt{(9)-244}}{2}\\&#10;s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
8 0
3 years ago
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