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Rashid [163]
2 years ago
8

Avery got on the bus at 1:25 P.M. The trip took 74 minutes. Then she walked for 61 minutes to get home.

Mathematics
1 answer:
AnnZ [28]2 years ago
6 0

Answer:

3:40 p.m.

Step-by-step explanation:

Add 74 minutes to 1:25 p.m.; the improperly formed result witll be 1:99 p.m.; to express this properly, add 1 hour to this time and subtract 60 minutes from it:

2:39 p.m. (time at which Avery gets off the bus)

If Avery walked 61 minutes to get home and we want to know what time she arrived, we add 61 minutes to 2:39 p.m., obtaining 2:100 p.m., which must in turn be re-written as 3:40 p.m.

Avery arrived home at 3:40 p.m.

Note:  another way in which to do this problem is to add 74 minutes and 61 minutes, obtaining 135 minutes, and then adding 135 minutes to 1:25 p.m. and making the necessary adjustments to the result:

1:25 p.m. + 135 minutes = 1:160 p.m., or (recognizing that 120 min = 2 hours)

3:40 p.m.

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Answer:5

Step-by-step explanation:

Since Michelle (he ? ) has 11/12 quarts of paint, and need 1/6 per quart to paint, we do 11/12 / 1/6 = 11/2, or 5.5. We cannot paint .5 of a block, so Michelle can only paint 5 quarts.

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3 years ago
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Answer:

3/2 mph

Step-by-step explanation:

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3 years ago
Alex needs 36 boxes in the carton above.
olganol [36]

Answer:

1 stack of 36

Step-by-step explanation:

First find how much one carton can hold

length is 45

width is 20

height is 40

40 * 20 * 45 = 36,000

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A sandbag is released from a hot air balloon that is 400ft above the ground. Using the falling object model, h = –16t2 + s, wher
Aleonysh [2.5K]

<u>Answer</u>:

It takes 5 seconds for the sandbag to hit the ground

<u>Explanation</u>:

Given:

Height at which the sand bag is released from the hot air balloon= -400 f t

To find:

Time taken for the sandbag to hit the ground, t =?  

Solution:

The initial height =s

Initially the height will be 0

Hences=0

the falling object model equation  

h=-16 t^{2}+s

Substituting the values we get,

h=-16 t^{2}+s

400=16 t^{2}

t^{2}=\frac{400}{16}

t^{2}=25

t=\sqrt{25}

t=5 \text { seconds }

Result:

Thus it takes 5 seconds for the sandbag to hit the ground

3 0
3 years ago
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