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3 years ago

(Cscx+1)/(casx-1)=(1+senx)/(1-Senx)

Mathematics

1 answer:

emmasim [6.3K]3 years ago

5 0

Are you supposed to do all the ones in the quotations?

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One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago

PRE CALCULUS

Mumz [18]

Start with the parent function f(x) = x³

Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.

Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate

Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x) is translated five units up

So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.

3 0

3 years ago

Which of the following square root of -80

Marta_Voda [28]

You can factor -80 as

$-80 = (-1)\cdot 16 \cdot 5$

So, we have

$\sqrt{-80} = \sqrt{(-1)\cdot 16 \cdot 5}$

The square root of a product is the product of the square roots:

$\sqrt{-80} = \sqrt{(-1)}\sqrt{16}\sqrt{5}$

Since $i^2=-1$ and $4^2=16$ , we have

$\sqrt{-80} = 4i\sqrt{5}$

8 0

3 years ago

What time is 90° counterclockwise?

erastova [34]

3:00 I think. :-)

Hope that helped

7 0

3 years ago

Write each expression in simplest form. (√y-√3)(√y+2√3)

Vladimir79 [104]

We write the expression in its simplest form and we are left with.

y²√3 + y - 6

Before proceeding let's define an algebraic expression.

<h3>Algebraic expression</h3>

An algebraic expression is a set of numbers and letters that make up an expression that has a meaning, the letters are variables and the numbers are coefficients or independent terms, algebraic expressions can be part of an equation and model mathematical processes.

The first thing we will do is to write the expression:

(√y-√3)(√y+2√3)

Then we perform the multiplication, with the distributive property, which gives as a result

(y + 2√3y - √3y - 6)

y²√3 + y - 6

Learn more about algebraic expression in:

brainly.com/question/21856579

#SPJ4

4 0

1 year ago