Answer:
762 days
Step-by-step explanation:
Given
Let the rate be R.
So the rate change with time is represented as:
So:
To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3
i.e.
becomes
Integrate
![R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0]](https://tex.z-dn.net/?f=R%20%3D%20200t%20%2B%20%5Cfrac%7B10t%5E2%7D%7B2%7D%20%2B%20%5Cfrac%7B13t%5E3%7D%7B3%7D%20%5B3%2C0%5D)
Solve for R by substituting 0 and 3 for t
<em>The population of insect between the required interval is 762</em>
Answer:
what questions? I dont see any
Answer:
I would find it by multiplying -3x-2 and getting six. Then I would multiply -1x2 and get -2 then I would add six and -2 and get 4.
Step-by-step explanation:
Answer:
-37
Step-by-step explanation:
Simplifying
74 + 2x = 0
Solving
74 + 2x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-74' to each side of the equation.
74 + -74 + 2x = 0 + -74
Combine like terms: 74 + -74 = 0
0 + 2x = 0 + -74
2x = 0 + -74
Combine like terms: 0 + -74 = -74
2x = -74
Divide each side by '2'.
x = -37
Simplifying
x = -37
