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mote1985 [20]
4 years ago
12

Identify which of the statements is true. −36.5 > −36.07 −2.6 > 2.521 −8.0329 > −8.045 −0.4 > −0.004

Mathematics
1 answer:
max2010maxim [7]4 years ago
7 0
For the numbers with negative sign, the larger the numerical value following the negative sign, the lower is the value of the number. The symbol, ">" means "greater than". 

From the inequalities given above, the one that makes exact sense is,
     -8.0329 > -8.045

Hence, the answer to this item is the third choice. 
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Olegator [25]

(  (\frac{3}{5})  {}^{0} ) {}^{ - 2}  = (1) {}^{ - 2}  =  \frac{1}{1 {}^{2} } =  \frac{1}{1}  = 1

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2 years ago
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What is 04.151515... into a fraction
Sergio039 [100]

Answer:

\displaystyle 4.\overline{15} = \frac{137}{33}.

Step-by-step explanation:

Start by separating this decimal number into its integer part and its fraction part:

4.151515\cdots = 4 + 0.151515\cdots

The most challenging task here is to express 0.151515\cdots as a proper fraction. Once that fraction is found, expressing the original number 4.151515\cdots will be as simple as rewriting a mixed number as an improper fraction.

Let x = 0.151515\cdots. (x + 4) would then represent the original number.

Note that the repeating digits appear in groups of two. Therefore, if the digits in x are shifted to the left by two places, the repeating part will continue to match:

\begin{aligned}x = 0.&151515\cdots && \\ 100\, x = 15.& 151515\cdots \end{aligned}.

Note, that this "shifting" is as simple as multiplying the initial number by 100 (same as 10 raised to the power of the number of digits that needs to be shifted.)

Subtract the original number from the shifted number to eliminate the fraction part completely:

\begin{aligned}&(100\, x) - x \\ &= 15.151515\cdots\\  & \phantom{=}- 0.151515\cdots\\&=15 \end{aligned}.

In other words:

99\, x = 15.

\displaystyle x = \frac{15}{99} = \frac{5}{33}.

Therefore, the original number would be:

\displaystyle x + 4 = \frac{5}{33} = \frac{132 + 5}{33} = \frac{137}{33}.

4 0
3 years ago
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
3 years ago
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