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3 years ago

Identify which of the statements is true. −36.5 > −36.07 −2.6 > 2.521 −8.0329 > −8.045 −0.4 > −0.004

1 answer:

max2010maxim [7]3 years ago

7 0

For the numbers with negative sign, the larger the numerical value following the negative sign, the lower is the value of the number. The symbol, ">" means "greater than".

From the inequalities given above, the one that makes exact sense is,
-8.0329 > -8.045

Hence, the answer to this item is the third choice.

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Can someone help me for this question please? Why I got wrong answer. ASAP!!!

Snowcat [4.5K]

Answer:

a=8.06

A=29.74

B=60.26

Step-by-step explanation:

This is a right angled triangle and Pythagoras theorem is to be obeyed.

To get c, we follow the Pythagoras rule that says

Hyp² = Opp² + Adj²

c= Hypotenuse

c²= a² + b²

c² = 4² + 7²

c² = 65

c = √65 = 8.06

For angle A,

the opposing side to the angle = a = 4

The adjacent side to the angle = b = 7

Following trigonometry rule.

Tan A = opp/adj

Tan A = 4/7

A = Tan–¹(4/7)

A = 29.74°

For angle B,

Opposing side = 7

Adjacent side = 4

Tan B = 7/4

B = Tan-¹(7/4)

B = 60.26°

5 0

3 years ago

How do you solve 2(x+7)+x=20

alexira [117]

2(x+7) + x=20
(2)(x) + (2)(7) + x=20 Distribute
2x+14 + x =20
(2x+x) + (14) =20 Combine Like Terms
3x+14=20
- 14 -14 Subtract 14 from both sides
3x = 6
3x/3 6/3 Divide Both Sides by 3

x = 2

Let me know if you still don't understand

4 0

2 years ago

Triangle ABC is a triangle with no equal sides. A new triangle congruent to triangle ABC is to be placed on the plane such that

Margarita [4]

Answer:

Step-by-step explanation:

im bad at explaining

6 0

2 years ago

I don’t know how to do this

stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as $x$ approaches the edges. For example,

$g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}$

has two pieces, $2x+5$ and $x^2-10$ , both of which are continuous by themselves on the provided intervals. In order for $g$ to be continuous everywhere, we need to have

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)$

By definition of $g$ , we have $g(-3)=2(-3)+5=-1$ , and the limits are

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1$

$\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1$

The limits match, so $g$ is continuous.

For the others: Each of the individual pieces of $f,h$ are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.