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mote1985 [20]
3 years ago
12

Identify which of the statements is true. −36.5 > −36.07 −2.6 > 2.521 −8.0329 > −8.045 −0.4 > −0.004

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0
For the numbers with negative sign, the larger the numerical value following the negative sign, the lower is the value of the number. The symbol, ">" means "greater than". 

From the inequalities given above, the one that makes exact sense is,
     -8.0329 > -8.045

Hence, the answer to this item is the third choice. 
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Please helppppppppppppp​
aleksley [76]

Answer:

The circumference is 18.84 inches.

Step-by-step explanation:

To find the circumference of the circle we can use the formula:

C=2\pi r

Where C is circumference and r is radius.

Now that we have the formula, we can substitute the numbers:

C=2(3.14*3)\\C=2(9.42)\\C=18.84

8 0
2 years ago
Read 2 more answers
Find the equation of the line tangent to the graph of f(x)=(lnx)^(4)at x=10
Diano4ka-milaya [45]

Hello,

Step-by-step explanation:

f(x) = ln(x) {}^{4}

(ln(u)') =  \frac{u'}{u}

f'(x) =  \frac{4ln {}^{} (x) {}^{3} }{x}

f'(10) =  \frac{4ln {}^{} (10) {}^{3} }{10}  =  \frac{12ln(x)}{x}

f(10) = ln(10) {}^{4}

y =  \frac{12ln(x)}{x} (x - 10) + 4ln(10)

y = f'(a)(x - a) + f(a)

4 0
2 years ago
What value of x is a solution to x3 = 216?
Ymorist [56]

Answer:

X=72

Step-by-step explanation:

216/3= 72

5 0
3 years ago
When completing the square, does the value of A always need to be one?<br> Thanks
Greeley [361]

Yeah, mostly is has to be negative, but in some cases a is greater than 1 than we do some other operations.

4 0
3 years ago
If f(x) is a linear function, f(−2)=4, and f(1)=−1, find an equation for f(x)
juin [17]

Answer:

y = -\frac{5}{3}x+\frac{2}{3}

Step-by-step explanation:

Given

f(-2) = 4

f(1) = -1

Required

The equation of the function

The given parameters means that:

(x_1,y_1) = (-2,4)

(x_2,y_2) = (1,-1)

Calculate the slope (m)

m = \frac{y_2 -y_1}{x_2 -x_1}

m = \frac{-1-4}{1--2}

m = \frac{-5}{3}

The equation is then calculated using:

y = m(x - x_1) + y_1

This gives:

y =\frac{-5}{3}(x--2)+4

y =\frac{-5}{3}(x+2)+4

Open bracket

y = -\frac{5}{3}x-\frac{10}{3}+4

Take LCM

y = -\frac{5}{3}x+\frac{-10+12}{3}

y = -\frac{5}{3}x+\frac{2}{3}

6 0
3 years ago
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