Answer:
m∠XBC = 135
Step-by-step explanation:
What is the measure of ∠XBC?
m∠XBC = m∠BAC + m∠BCA
3p – 6 = p + 4 + 84
3p – 6 = p + 88
2p – 6 = 88
2p = 94
From the simplified expression, we need to find the value of p first
From the last line we can see that;
2p =94
Divide both sides by 2:
2p/2 =94/2
p = 47
From the expression, m∠XBC =3p-6
m∠XBC = 3(47)-6
m∠XBC = 141 -6
m∠XBC = 135
Hence the measure of m∠XBC is 135
Y=x+1
You can solve using slop formula
Answer:
yes
Step-by-step explanation:
try using a vertical line, if you move the vertical line across the graph and the line touches the graph only at one point, than it means it is a function
ONP=43 degrees
LNO=137 degrees
MNP=137 degrees
A straight line equals 180 degrees, so the angles need to add up to that amount. Hope this helps!
Answer:
119.05°
Step-by-step explanation:
In general, the angle is given by ...
θ = arctan(y/x)
Here, that becomes ...
θ = arctan(9/-5) ≈ 119.05°
_____
<em>Comment on using a calculator</em>
If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.
__
It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...
Tan = Opposite/Adjacent = |y|/|x|
This is the tangent of the reference angle, which will be ...
θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°
You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.
