Please Help Me with this problem

Mathematics

1 answer:

Alex Ar [27]3 years ago

3 0

Answer:

AEB =305° as stated below

Step-by-step explanation:

AEB is the larger area starting A to EB and missing out the small AB area

EC = 180° = supplementary we label 87° angle to P.

P+ BCD = 87, + 38 = 125°

ABCD = 180°

180 - BCD = 180-125°

AB = 55°

Therefore AEB = 360-55=305°

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Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the distance formula, which is really just the Pythagorean Theorem rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .