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3 years ago

How many pairs of whole numbers add up to 99

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

50 pairs

With the sum of 99, we will get 50 pairs whole numbers. Why? Therefore, if you're going to count all pairs of whole number, you will get 50 pairs of whole number with the sum of 99

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Help please desperate!!

zhenek [66]

Answer:

Step-by-step explanation:

$V=\pi r^2h\\=\pi *4^2*3\\=48\pi$

7 0

3 years ago

2 1/4(4x-1)=1 3/5(1+4x)?? I need help with this problem. Thanks!!

koban [17]

Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Step-by-step explanation:

We need to solve the problem: $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$

Solving:

$2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)\\\frac{9}{4}(4x-1)=\frac{8}{5}(1+4x)\\9x-\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}$

Add 9/4 on both sides:

$9x-\frac{9}{4}+\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}+\frac{9}{4}$

$9x=\frac{8}{5}+\frac{9}{4}+\frac{32x}{5}\\9x-\frac{32x}{5}=\frac{8}{5}+\frac{9}{4}\\\frac{9x*5-32x}{5}=\frac{8*4+9*5}{20}\\\frac{45x-32x}{5}=\frac{32+45}{20}\\\frac{13x}{5}=\frac{77}{20}\\x=\frac{77}{20}\times \frac{5}{13}\\x=\frac{77}{4*13}\\x=\frac{77}{52}$

So, Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Keywords: Solving Fractions

Learn more about Solving Fractions at:

#learnwithBrainly

8 0

4 years ago

Write the equation in slope intercept form. what are the slope and y-intercept? -3x - 10y = 7

blondinia [14]

slope intercept is basically solve for y y=mx+b m=slope b=yintercept -3x-10y=7 add 3x to both sides -10y=3x+7 divide both sides by -10

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3 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

WILL GIVE BRAINLIST What is the volume of the cylinder below?

azamat

Answer:

Volume of the given oblique cylinder = 36π units³

Step-by-step explanation:

Volume of the oblique cylinder = πr²h

Here, 'r' = Radius of the circular base

'h' = Height of the cylinder

For the given oblique cylinder,

Radius of the circular base = 3 units

Height of the cylinder = 4 units

Volume of the cylinder = π(3)²(4)

= 36π units³

Therefore, volume of the given oblique cylinder = 36π units³

4 0

3 years ago