The answer is having fewer neutrons than protons or electrons.
Answer:
the image is virtual and erect and the lens divergent; therefore the correct answer is C
Explanation:
In a thin lens the magnification given by
m = h '/ h = - q / p
where h ’is the height of the image, h is the height of the object, q is the distance to the image and p is the distance to the object.
It indicates that the object is straight and is placed at a distance p> f
analyze the situation tells us that the magnification is positive so the distance to the image must be negative, that is, that the image is on the same side as the object.
Consequently the lens must be divergent
The magnification value is
0.4 = h ’/ h
h ’= 0.4 h
therefore the erect images
therefore the image is virtual and erect and the lens divergent; therefore the correct answer is C
Silicon is in fact a Metalloid. Comment if you need more info!
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Distance of R/2:
Since a conducting sphere is referenced in this situation, all of its charge will be distributed along its SURFACE. Therefore, there is NO enclosed at a distance of R/2 from the center.
Using Gauss's Law:
E = Electric field strength (N/C)
A = Area of Gaussian surface (m²)
Q = Enclosed charge (C)
ε₀ = Permittivity of free space C²/Nm²)
If the enclosed charge is 0, then:
Distance of '2R':
We can once again use Gauss's Law to solve. This time, however, a surface of radius '2R' encloses ALL of the charge of the sphere.
'A' is equivalent to the surface area of a sphere of radius '2R', or:
Substituting this expression back into Gauss's Law:
To simplify:
OR using k = 1/4πε₀: