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3 years ago

Which of the following defines "frequency"?

Physics

1 answer:

I am Lyosha [343]3 years ago

8 0

the distance between adjacent peaks in a series of periodic waves

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Qroups of specialized cells that work together are called____

kiruha [24]

Groups of cells make tissues.
Groups of tissues make organs.
Groups of organs make organisms.
Groups of organisms make communities.
The BOLD sentence above is your answer.

4 0

3 years ago

A less-dense liquid of density rho1 floats on top of a more-dense liquid of density rho2. A uniform cylinder of length l and den

Umnica [9.8K]

Answer:

Explanation:

Given

$\rho=density\ of\ cylinder\\\rho_1=less\ dense\ cylinder\\\rho_2=more\ dense\ cylinder$

Suppose V is the volume of a cylinder

Also $L_1=length\ in\ less\ dense\ part\\L_2=length\ in\ dense\ part\\L=length\ of\ cylinder\\V=A\times L\\where\ A=area\ of\ cross-section\\$

Now, we can write

The weight of the cylinder is supported by the buoyant forces of two liquids

$\rho Vg=\rho_1 V_1g+\rho_2 V_2g\\\rho ALg=\rho_1 A\times L_1g+\rho_2 A\times L_2g\\\\\rho L=\rho_1 L_1+\rho_2 L_2\\Also, L=L_1+L_2$

using the above equation we can write

$L_2=\frac{\rho-\rho_1}{\rho_2-\rho_1}\cdot L\\\frac{L_2}{L}=\frac{\rho-\rho_1}{\rho_2-\rho_1}$

5 0

3 years ago

What does the column that an element is in tell you?

Mumz [18]

Answer:

The column number tells us the amount of valence electron the element has

8 0

3 years ago

60 point!!!

erastova [34]

Answer:

Playing hockey, driving a car, and even simply taking a walk are all everyday examples of Newton's laws of motion.

7 0

3 years ago

A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t

Archy [21]

Answer:

$A=81mm^2$

Explanation:

We know that for a capacitor $Q=CV$ , where Q is the charge of one plate, C the capacitance and V the potential between the plates.

We also know that $Q=\sigma A$ , since $\sigma$ is the surface charge density and A the area of the plate (both equal in our case).

Putting all together:

$A=\frac{CV}{\sigma}$

Which for our values is:

$A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2$

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that $mm^2$ is enough to describe an area).

8 0

3 years ago