Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Answer:
It's totally correct with no doubt
Answer:
x = 30m
Step-by-step explanation:
<u>GIVEN :-</u>
There are 2 right-angled triangles.
In the triangle on the right side ,
- Hypotenuse = 26m
- Base = 10m
In the triangle on the left side ,
<u>TO FIND :-</u>
- Length of the common perpendicular to both triangles.
- Length of the hypotenuse of the triangle on the left side.
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
.
<u>SOLUTION :-</u>
In the triangle on the right side ,

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.
In the triangle on the left side ,

∴ x = 30m
Answer:
A.
Step-by-step explanation:
Answer:
hmhmhmhh hkm ntyiod dfov
Step-by-step explanation: