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4 years ago

Both cases?

Mathematics

1 answer:

pishuonlain [190]4 years ago

8 0

Answer:16.7 percent that what I got

Step-by-step explanation:

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fond two consecutive odd integers whose sum is 36 which of the following equations could be used to solve the problem

Travka [436]

Answer:

17 is the answer.

Step-by-step explanation:

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4 years ago

Katrina is reading a book that is 400 pages long. She has read 340 pages so far.

Svetach [21]

$\frac{340}{400}=\frac{340 \div 4}{400 \div 4}=\frac{85}{100}=85\%$

Katrina has read 85% of her book.

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3 years ago

David uses 1/4 cup of apple juice for every 1/2 cup of carrot juice to make a fruit drink . Enter the number of cups of apple ju

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1/2 cup

Step-by-step explanation:

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3 years ago

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3 years ago

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A recent survey of students at John Tukey High School revealed that

RoseWind [281]

Answer:

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor, or they are not. Students are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

18% of the students are in favor of changing the dress code.

This means that $p = 0.18$

You randomly select 15 students

This means that $n = 15$

What is the probability that at least three of these students are in favor of the proposal to change the dress code?

This is

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.18)^{0}.(0.82)^{15} = 0.051$

$P(X = 1) = C_{15,1}.(0.18)^{1}.(0.82)^{14} = 0.1678$

$P(X = 2) = C_{15,2}.(0.18)^{2}.(0.82)^{13} = 0.2578$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.051 + 0.1678 + 0.2578 = 0.4766$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.4766 = 0.5234$

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

8 0

3 years ago