Answer:
42 gallons 45% antifreeze
28 gallons 95% antifreeze
Step-by-step explanation:
If x is volume of 45% antifreeze, and y is volume of 95% antifreeze, then the total volume is:
x + y = 70
And the total amount of antifreeze is:
0.45 x + 0.95 y = 0.65 (70)
Solving by substitution:
0.45 x + 0.95 (70 − x) = 0.65 (70)
0.45 x + 66.5 − 0.95 x = 45.5
21 = 0.5 x
x = 42
y = 28
Its Gonna be Hours Divided by rooms.
<span>=<span><span><span><span><span><span><span>2x</span>+<span>−<span>8x</span></span></span>+<span>−<span>6y</span></span></span>+9</span>+<span>−14</span></span>+x</span>+<span>11y
</span></span></span><span>=<span><span><span>(<span><span><span>2x</span>+<span>−<span>8x</span></span></span>+x</span>)</span>+<span>(<span><span>−<span>6y</span></span>+<span>11y</span></span>)</span></span>+<span>(<span>9+<span>−14</span></span><span>)
= -5x+5y+-5
= -5x+5y-5
Answer is = -5x+5y-5
</span></span></span></span>
Answer:
1 inch = 3 feet
Step-by-step explanation:
A scale drawing is a reduced form in terms of dimensions of an original image / building / object
the scale drawing is usually reduced at a constant dimension
scale of the drawing = original dimensions / dimensions of the scale drawing
6 /2 = 3
1 in = 3 feet
Answer:
![T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]](https://tex.z-dn.net/?f=T%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%20%26%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%26%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let General Transformation matrix be denoted as T
Step 1: Clockwise rotation of 45 degrees
General counterclockwise rotation matrix in 2-dimension is given as
![R(\theta)=\left[\begin{array}{ccc}cos\theta & - sin\theta\\sin\theta&cos\theta\\\end{array}\right]](https://tex.z-dn.net/?f=R%28%5Ctheta%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dcos%5Ctheta%20%26%20-%20sin%5Ctheta%5C%5Csin%5Ctheta%26cos%5Ctheta%5C%5C%5Cend%7Barray%7D%5Cright%5D)
For clockwise rotation we need to insert θ as negative in the above matrix. Therefore, the resulting matrix is
![R(-\theta)=\left[\begin{array}{ccc}cos\theta & sin\theta\\-sin\theta&cos\theta\\\end{array}\right]](https://tex.z-dn.net/?f=R%28-%5Ctheta%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dcos%5Ctheta%20%26%20sin%5Ctheta%5C%5C-sin%5Ctheta%26cos%5Ctheta%5C%5C%5Cend%7Barray%7D%5Cright%5D)
as sin(-θ) = -sin (θ) and cos(-θ) = cos (θ)
For 45 degrees
and 
![R(-45)=\left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]](https://tex.z-dn.net/?f=R%28-45%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%20%20%26%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%26%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step 2: Reflection through line y = x
This type of reflection maps (x,y)→(y,x)
Therefore the general matrix is
![R(x,y)=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=R%28x%2Cy%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Step 3: General Transformation Matrix
T = R(x,y) R(-θ)
![T=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]](https://tex.z-dn.net/?f=T%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%20%20%26%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%26%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
