<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
Answer:
Less than 100. Z=83
Step-by-step explanation:
The mean is the average found by adding the sum of the data points and dividing by the number of them. Here there are 3 cars whose speeds are 101, 116, and Z or unknown. The mean of them is 100. Solve for Z.
100 =(101+116+Z)/3
300=217+Z
83=Z
Alright so the parentheses mean (x, y) so basically you have to plug in the numbers in parentheses into the equation so here's what I got:
a. i
b. iv
c. ii
d. v
So then e must be iii, let’s check:
y = -x + 1
.5 = -.5 + 1 ✔️
.75 = -.25 + 1 ✔️
.875 = -.125 + 1 ✔️
So that’s how you would solve those equations. Hope this helps.
Answer: B. A coordinate plane with points in quadrants II and IV.
Step-by-step explanation:
Let's take the point (-1,1) as an example
The point itself is in the second quadrant
the opposite of the point is (1,-1)
This point is in the fourth quadrant
