See the attached picture:
Answer:
The minimum distance x that a plant needing full sun can be placed from a fence that is 5 feet high is 4.435 ft
Step-by-step explanation:
Here we have the lowest angle of elevation of the sun given as 27.5° and the height of the fence is 5 feet.
We will then find the position to place the plant where the suns rays can get to the base of the plant
Note that the fence is in between the sun and the plant, therefore we have
Height of fence = 5 ft.
Angle of location x from the fence = lowest angle of elevation of the sun, θ
This forms a right angled triangle with the fence as the height and the location of the plant as the base
Therefore, the length of the base is given as
Height × cos θ
= 5 ft × cos 27.5° = 4.435 ft
The plant should be placed at a location x = 4.435 ft from the fence.
Answer:
1.First Move the decimal point in the divisor and dividend.
2.Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.
3.Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.
Step-by-step explanation:
I got it from google tbh
Answer:
The Sum of the areas of theses triangles is 169/3.
Step-by-step explanation:
Consider the provided information.
The hypotenuse of an isosceles right triangle is 13 inches.
Therefore,

Then the area of isosceles right triangle will be: 
Therefore the area is: 
It is given that sum of the area of these triangles if this process is continued infinitely.
We can find the sum of the area using infinite geometric series formula.

Substitute
in above formula.



Hence, the Sum of the areas of theses triangles is 169/3.
Answer:
cheat off somebody who has the answer
Step-by-step explanation: