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Bezzdna [24]
3 years ago
9

What number can be written as six hundred forty-seven?

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
647? Not completely sure if that’s the answer you’re looking for.
vladimir2022 [97]3 years ago
4 0
647 that is how your write it. 
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X – y +z = 5<br> x + y + 2z = 19<br> x + y + z = 15
otez555 [7]

Answer:

x=5,y=5,z=5

Step-by-step explanation:

x=15-y-z

15-y-z-y+z=5

15-2y=5

y=5

x+y+z=15

15-2y+y+z=15

15-10+5+z=15

z=5

x-y+z=5

x-5+5=5

x=5

8 0
3 years ago
Mai is making personal pizzas. For 4 pizzas, she uses 10 ounces of cheese. How much cheese does she use for each pizza?
Delvig [45]

Answer:

2.5 ouces

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Show me how to graph f(x)=3/2 x + 2
Alexxx [7]

y = (3x)/2 + 2

Slope = 3/2

y-intercept = 2


The first point is y-intercept when x = 0 = (0,2). Now according to our slope we move 3 up (Why up? Because it's positive) and 2 right (Why right? Because it's positive).

When you move 3 up from (0,2), you get (0,5) and move 2 right which is (2,5).

Remember: slope = change in y / change in x


Points: (0,2) and (2,5)

3 0
3 years ago
PLEASE HELP The volume of a cube is defined by the function, V(x), where the volume is measured in cubic meters. Find a polynomi
olya-2409 [2.1K]

we have

V(x)=x^3-12x^2+48x-64

we know that

The volume of a cube is equal to

V=b^{3}

where

b is the length side of a cube

Using a graph tool------> find the roots of the polynomial

see the attached figure

x=4

so

x^3-12x^2+48x-64=(x-4)^{3}

therefore

<u>The answer is</u>

the length side of a cube is equal to (x-4)

5 0
3 years ago
An object is acted upon by the forces F1=&lt;10​,6​,4&gt; and F2=&lt;0​,3​,9&gt;. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
3 years ago
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