What’s something goes up but never comes down?
<span>Find the inverse of the given function.
f(x) = -1/2√x + 3, x ≥ -3
I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3. If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.
1. Replace "f(x)" by "y:" y </span>= -(1/2)sqrt(x) + 3
2. Interchange x and y: x = -(1/2)sqrt(y) + 3
3. Solve for y: x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4. Replace "y" with
-1
f (x) = sqrt(2[3-x])
Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers. The domain here is (-infinity,3]
The formula for the area of a rectangle is A = bh.
Substitute 216.24 for A (area) and 15.9 for h (height).
A = bh
216.24 = b(15.9)
÷ 15.9 ÷ 15.9 Divide 15.9 on both sides.
13.6 = b
So, the base of the rectangle is 13.6 cm.
Answer:
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