find three consecutive odd integers such that the square of the first plus the square of the third is 170
1 answer:
Here is the set up:
x
x + 2
x + 4
x^2 + (x + 2) + (x + 4)^2 = 170
Take it from here.
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4x^2+19x-5
Factored form
= (4x - 1)(x + 5)
Hope it helps
Answer:
TSA=115.5cm²
Step-by-step explanation:
T.S.A=3πr²
Given r=3.5cm
eq.
3×22/7×3.5×3.5
=3×22×0.5×3.5
=115.5cm²
Yea -p = 3
so divide both sides by -1:-
-p / -1 = 3 / -1
p = -2 <------ that's your solution
X = 6 / tan(67)
x = 2.546
rounded to nearest tenth x = 2.5
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