A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t


Solve for t


Solve using quadratic formula


After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
5.4
Step-by-step explanation:
3x+38=10x
-3x -3x
38=7x
x=5.4
Brainliest pleaseeeeeee
Answer:
42
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
54=2x3x3x3
12=2x2x3
common factors are 2 and 3 so 2x3=6
Answer:
the answer is 15.
Step-by-step explanation:
you find the answer by turning 25% into 0.25 then you multiple it by 60, this results in 15.