Check the picture below.
since the second figure is also a square, then the sides touching the diagonals have to be all equal, and that'd only happen if those sides bisects the larger square's diagonal.
Answer:
See below
Step-by-step explanation:
The initial ordered-pairs are 
We have a rotation of 90 degrees counterclockwise with respect to origin
Note. Previously the points were
After the rotation, we have
Thus, 
Then shifting horizontally to the right 2 units, we get ΔA'B'C'
Thus,
Answer:
<em><u>1.c</u></em>
<em><u>2.b</u></em>
<em><u>3.a</u></em>
<em><u>4.d</u></em>
<em><u>5.c</u></em>
Step-by-step explanation:
<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>☻</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☺️</u></em><em><u>❤</u></em><em><u>☻</u></em>
A^-b is the same as 1/a^b.
When there is a negative power, place the number and power over 1.
a^b/a^c = a^(b-c).
c is a negative power, because it is being divided, and is underneath b, which is a positive (and so it stays in the numerator).
a^c/b^c = (a/b)^c
Inside this one, the power of c is distributed to all numbers inside the parenthesis, in this case a and b.
hope this helps
