Look at one of the vertices of the heptagon where two squares meet. The angles within the squares are both of measure 90 degrees, so together they make up 180 degrees.
All the angles at one vertex must clearly add up to 360 degrees. If the angles from the squares contribute a total of 180 degrees, then the two remaining angles (the interior angle of the heptagon and the marked angle) must also be supplementary and add to 180 degrees. This means we can treat the marked angles as exterior angles to the corresponding interior angle.
Finally, we know that for any convex polygon, the exterior angles (the angles that supplement the interior angles of the polygon) all add to 360 degrees (recall the exterior angle sum theorem). This means all the marked angles sum to 360 degrees as well, so the answer is B.
If you want to find the solutions for this you have to factor it. Since it's a second degree polynomial, you'll have 2 solutions. Factoring this using the quadratic formula, you'll get factors of (5x-8)(3x-4). Solving these for x you get x = 8/5 and x = 4/3.
It is irrational because it is a decimal that doesn't terminate or repeat! :)
Answer:
x=48
Step-by-step explanation:
the 2 given angles if added together we know it’ll be 180 degrees
3x-12+x=180
4x-12=180
+12. +12
4x=192
x=48
Hopes this helps please mark brainliest
