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4 years ago

Formula for circumference

Mathematics

2 answers:

FromTheMoon [43]4 years ago

6 0

Answer:

3.14 time the diameter of the circle

Step-by-step explanation:

Licemer1 [7]4 years ago

5 0

Answer:

pi x diameter

Step-by-step explanation:

To calculate the circumference of a circle, simply multiply pi (3.14) by the diameter (straight line passing from side to side through the center of the circle)

For instance, if you knew the diameter of a circle was 6 inches. Simply multiply 6 inches by pi!

6 x pi = ?

? approximately equals 18.85 inches.

The circumference of the circle would be 18.85 inches!

If you only have the radius of the circle, simply multiply it by two to get your diameter. Remember, the radius is just half the length of the diameter.

Hope this helps! :)

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The world's tallest man cast a

klemol [59]

Answer:

Step-by-step explanation:

It's a matter of proportions.

Let's call them A and B. Now, let's make an equation.

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Now that we know that...

$A = \frac{535}{5} = 107 in = 8 ft 11 in$

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3 years ago

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3 years ago

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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

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$PM^2=(6)^2+(8)^2$

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$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

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From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

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Inessa [10]

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The percent of increase or decrease of the with time

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ipn [44]

Answer:

Step-by-step explanation:

We'll note the numbers as $x_{n}, x_{n+1} ...$

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3 years ago

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