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Vitek1552 [10]
3 years ago
15

NEED HELP ASAP Which of the following equations describe the line shown below?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4

y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b

so the equation is : y = -4x + 2 <=== here is one

y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one

y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
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Choose the equation in slope-intercept form of a line with the following qualities:
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5 0
2 years ago
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kkurt [141]

Answer:

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1  

If you have the expression:

(x- \frac{2}{5})^{2}

You can write the expression it in the following way:

(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})

Then, apply the distributive property:

(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}

Simplify the expression:

(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

(a-b)^2

Its expanded form will be:

(a-b)^2= a^2 -2ab + b^2

If

a = x

b =\frac{2}{5}

(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

3 0
3 years ago
5/4 miness 5/8what does it equal ​
Ivan
Answer:
5/8
explanation:
5/4(2)=10/8-5/8
4 0
3 years ago
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