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valkas [14]
3 years ago
13

A carpenter has a board that is 2/3 yard wide. He cuts the board into 5 pieces. If all the pieces are the same width, how wide i

s each piece?
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

\huge\boxed{\frac{2}{15} \text{        yards}}

Step-by-step explanation:

We have a board that is \frac{2}{3} yards long. If we want to cut the board into 5 <em>equal pieces</em>, we must divide \frac{2}{3}  by 5.

\frac{2}{3} \div 5

5 is the same thing as \frac{5}{1}, so:

\frac{2}{3} \div \frac{5}{1}

To divide a fraction by a fraction, we multiply by the reciprocal.<em> </em>This means we take the reciprocal of \frac{5}{1} and multiply the two fractions.

The reciprocal of \frac{5}{1}  is \frac{1}{5} - we swap the numerator and denominator.

\frac{2}{3} \cdot \frac{1}{5}

Multiply the numerator and denominators to get our final fraction:

2\cdot 1 = 2\\3 \cdot 5 = 15\\\\\frac{2}{15}

Hope this helped!

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Volume? Correct answers please
goldfiish [28.3K]

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V = 1385.44

Step-by-step explanation:

The equation for volume is V = π r 2 h! Where V = volume, r = radius <em>(half the diameter)</em>, and h = height. Now lets substitute what we know into this equation!

<em>Since we are giving the diameter (14) we must divide by 2 to find the radius.</em>

                         14 ÷ 2 = 7

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V = ?

Time to plug these values in!

V = π 7^{2} (9)

<em>We have to distribute </em><em>pi to 7 square that term </em><em>and then </em><em>multiply the value by 9</em><em>. </em>

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V = 1385.44

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

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7 0
3 years ago
3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu
djverab [1.8K]

Answer:

Probability distribution for x:

P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

So, we have this probabilty distribution for x:

P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\

7 0
3 years ago
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