1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pavel [41]
3 years ago
12

Which of the following variables for data about a track team is a discrete variable?a) The height of a team memberb) The weight

of a team memberc) The number of times that a team member finished first in a raced) The time recorded for the last race that was run by a team membere) The time recorded for a one-mile race by a team member
Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Discrete data includes numbers that are exclusively integers, i.e, ... -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 7 ..... and so on. It do not include the other real numbers that are not integers. You can recognize discrete data, for example, in a grah, as there will be only isolated points and not a continuous line.

The height of a member is continuous as we can have every number between 0 and the top height. There can be 1.50 m, 1.51m, 1.5000001m, 1.65m, 1,644444449, and so on with every number (obviously, we will not have heights of 5.78 m because of simply nature). So, we discard option a.

Exactly the same as heights happens with weight. We can ahve any weight you may imagine from the less weight to the top. 100.45555555 pounds is a posible weight, for example. With this, we discard option b.

The time is also continuous. Lets think in minutes. A runner can register 7 minutes, 7.2 minutes, 7.098686 minutes, and so on for every number. We can use every fraction you imagine. So we can discard options d and e.

However the number of times is discrete, because the number of races are discrete. There are 1, 2, 3, 4,... races. We can not have 5.5 races, it is impossible. So, the number of times a runner finished ahead is discrete. There is no member that finished 7.2 times first, we can find either 7 times or 8 times, but not 7.2. So, option c is the correct.

You might be interested in
Helpppppp pleaseeeeeeeeee
77julia77 [94]

Answer:

39.9km a day

Step-by-step explanation:

Add up the four kilometers cycled and you should get 159.6km cycled in total.  Divide that number by 4 to get 39.9km as a result.  So she's wrong.

7 0
3 years ago
Read 2 more answers
HELP!! Algebra help!! Will give stars thank u so much <333
Anna35 [415]

Answers:

  • Part a)  \bf{\sqrt{x^2+(x^2-3)^2}
  • Part b)  3
  • Part c)   2.24
  • Part d)  1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying d = \sqrt{x^2 + (x^2-3)^2} is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0
3 years ago
At Emily's summer camp, there are
Stells [14]

Answer:

15

Step-by-step explanation:

3 counselors for every 20 girls

6 0
3 years ago
Read 2 more answers
What is the area of a sector with a central angle of \frac{5 \pi }{6} radians and a diameter of 5.6 in.? Use 3.14 for π and roun
kvasek [131]

Answer:

10.26 in²

Step-by-step explanation:

The area (A) of the sector is

A = area of circle × fraction of circle

  = πr² × \frac{\frac{5\pi }{6} }{2\pi }

  = π × 2.8² × \frac{5}{12} ≈ 10.26 in²

7 0
3 years ago
If the dimensions of a pentagonal prism are quadrupled, then the surface area of the prism is multiplied by eight.
Lubov Fominskaja [6]

Answer:

false

Step-by-step explanation:

the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.

when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.

so, quadrupling the dimensions would multiply the areas by 16.

8 0
3 years ago
Other questions:
  • PLEASE ANSWER CORRECTLY AND QUICKLY!~
    7·1 answer
  • Evaluate the limit. 8n^+5n+2/3+2n
    9·1 answer
  • Find the missing terms in the following geometric sequence.
    9·1 answer
  • Mrs. Brown gives two tests to her class. 30% of the class passed both tests and 45% of the class passed the first test. What per
    10·1 answer
  • A rectangle has a side length of (8x+10) cm and a width of (5x-3)cm. The perimeter of the rectangle is 66cm .solve equation. wha
    5·1 answer
  • I need help with all of them thanks
    6·2 answers
  • Help please thanks<br> ................................
    13·2 answers
  • In order for an object to be a polygon it must have (choose the best answer) *
    13·2 answers
  • Can someone explain how to get the answer I’m confused on how to solve
    15·2 answers
  • Question 2 of 25
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!