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3 years ago

Which theorem shows that triangle ABC is approximately equal to triangle DEF?

Mathematics

1 answer:

Olin [163]3 years ago

4 0

Answer:

sss triangle congruence theorem

Step-by-step explanation:

Because in both triangle all sides are congruent that means you can use the sss triangle theorem to prove that ΔABC≅ΔDEF

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Which correlation coefficient corresponds to the best-fit line that most closely models its set of data?

Deffense [45]

The answer for this question is c

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3 years ago

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Answer I will mark your brainlist

yan [13]

Answer:

Mark C.

Step-by-step explanation:

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Since the <em>S</em> stands for the students absent, that should come after the brackets.

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3 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

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3 years ago

What percentage is 1100

kherson [118]

The answer is 100% percent

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3 years ago

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Can someone help me with these pls

Troyanec [42]

Answer:

subtract the area of the rectangle from the area of the triangle

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2 years ago