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3 years ago

Which theorem shows that triangle ABC is approximately equal to triangle DEF?

Mathematics

1 answer:

Olin [163]3 years ago

4 0

Answer:

sss triangle congruence theorem

Step-by-step explanation:

Because in both triangle all sides are congruent that means you can use the sss triangle theorem to prove that ΔABC≅ΔDEF

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Solve cot x + 2cot x * sin x = 0 for U^ <= x<=180

nekit [7.7K]

Answer:

Step-by-step explanation:

hello :

cot x + 2cot x sin x = 0 0≤ x≤ 180

cotx(1+2sinx) =0 means : cotx=0 or 1+2sinx=0

1) cotx=0 so : cosx=0 and sinx ≠ 0 because cotx = cosx/sinx

when : 0≤ x≤ 180 : x=90°

2) 1+2sinx=0 means : sinx = -1/2

when : 0≤ x≤ 180 : no solutions because : sinx ≥ 0

conclusion : one solution : x=90°

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3 years ago

55 points

cupoosta [38]

Answer:

160:40 or 160 to 40, 80:320 or 80 to 320, 400:1000 or 400 to 1000

Step-by-step explanation:

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3 years ago

Is 5400 perfect square?if not how it should cames 5400 by division

kap26 [50]

Answer:

73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54

8 0

2 years ago

hjlf

Idkhzslkkxkfof?&$ask a another girl for that answer

3 0

3 years ago

A bucket contains 40 red balls, 25 black balls, and 35 white balls. Two balls are drawn at random. What is the probability that

Lyrx [107]

Answer:

$Probability = \frac{1}{5}$ or $Probability = 0.2$

Step-by-step explanation:

Given

$Black = 25$

$White = 35$

$Red = 40$

Required

Determine the probability of selecting Black and Red

First, we need to calculate the number of red and black balls

The probability is calculated as thus:

$Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)$

Convert to mathematical expressions

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$

Solve for each probaility;

$P(Black) = \frac{Black}{Total} = \frac{25}{100}$

$P(Red) = \frac{Red}{Total} = \frac{40}{100}$

So, we have:

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$ $Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]$

$Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]$

$Probability = [\frac{1}{10}] + [\frac{1}{10}]$

$Probability = \frac{1+1}{10}$

$Probability = \frac{2}{10}$

$Probability = \frac{1}{5}$

$Probability = 0.2$

7 0

3 years ago