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3 years ago

The LCD of theses fractions? y/x + y/3+ y+1/y Answers: 3x+y x+3+y 3x+y

Mathematics

1 answer:

Dahasolnce [82]3 years ago

5 0

3xy

y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy 

NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. 

y(3y) + y(xy) + (y+1)(3x) 

3y^2 + xy^2 + 3xy +3x 

cannot simplify further.

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in triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. Find the perimeter o

alexdok [17]

since m and n are the midpoints of ab and ac resistively

then ,bc=2mn=16

since m and l are the midpoints of ba and bc respectively

then, ac =2mn =10

then,nc =1/2 × 10 =5

similary, mb=6

then ,perimeter=nc+mb+mn+bc=5+6+8+16=35

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3 years ago

He makes $316 a week and $23 for every sale he makes. He has to pay his rent this week that is $500, so he will need to make at

Lyrx [107]

let x be the number of sales Hayward needs to make

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3 years ago

during the 8-month shrimping season in the Gulf mexico, 325 shrimpers caught 4,913,977 pounds of shrimp and sold the shrimp $2 p

Hatshy [7]

STEP 1:
Find the $ total sold. Multiply total pounds by $2 sale price per pound.

=4,913,977 pounds * $2 a pound
=$9,827,954 total sold

STEP 2:
Divide the total sold above by the 325 shrimpers.

=$9,827,954 ÷ 325
=$30,239.858

Rounded to nearest dollar:
Each of the 325 shrimpers will take home $30,240.

Hope this helps! :)

4 0

2 years ago

Determine the center and radius of the following circle equation: x? + y2 - 2x - 12y +36 = 0

Gre4nikov [31]

Step-by-step explanation:

x²+ y² -12x - 18y +17 = 0 means : (x²-12x+36)-36+(y²-18y+81)-81-27 =0

(x-6)²+(y-9)² =12²....standard form when the center is (-6 , 9) and radius 12

3 0

2 years ago

Read 2 more answers

Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you

gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

scenario A: selecting a black card
scenario B: selecting a red card that is less than 5
scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

1/2 = 13/26
2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

$\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}$

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

$\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}$

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

7 0

2 years ago