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scZoUnD [109]
3 years ago
8

The LCD of theses fractions? y/x + y/3+ y+1/y Answers: 3x+y x+3+y 3x+y

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0
3xy 

<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>

<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>

<span>y(3y) + y(xy) + (y+1)(3x) </span>

<span>3y^2 + xy^2 + 3xy +3x </span>

<span>cannot simplify further.</span>
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4 years ago
Percents from Tabled Values
alexandr1967 [171]

Answer:

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Step-by-step explanation:

It is convenient to use a spreadsheet to total the numbers for you. This reduces errors and put the numbers in a form that makes it easy to see what you're working with in any given calculation.

  men with HS degree = (male HS)/(all male)

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<em>Comment on the problem</em>

The spreadsheet is identical to the one used for your other problem. All that needed to be done was to enter the new numbers. The formatting, headers, and formulas remained the same. For solving these problems, it's a matter of picking the two numbers needed from the appropriate row or column and computing their ratio.

(The computations were done by hand here to better show you the numbers used and the rounding to tenth percent. They can be done in the spreadsheet with point and click.)

3 0
3 years ago
Solve using the quadratic formula.<br>-v^2 + 9v - 5 = 0​
timama [110]

Answer:

v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2

Step-by-step explanation:

Solve for v over the real numbers:

-v^2 + 9 v - 5 = 0

Multiply both sides by -1:

v^2 - 9 v + 5 = 0

Subtract 5 from both sides:

v^2 - 9 v = -5

Add 81/4 to both sides:

v^2 - 9 v + 81/4 = 61/4

Write the left hand side as a square:

(v - 9/2)^2 = 61/4

Take the square root of both sides:

v - 9/2 = sqrt(61)/2 or v - 9/2 = -sqrt(61)/2

Add 9/2 to both sides:

v = 9/2 + sqrt(61)/2 or v - 9/2 = -sqrt(61)/2

Add 9/2 to both sides:

Answer: v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2

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X  > 0 and -x < y <span>< 2x There you go, it is infinite applying to those rules.</span>
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3 years ago
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