I’m pretty sure the answer is true
Answer:
Non-repudiation is the assurance that someone cannot deny the validity of something. Non-repudiation is a legal concept that is widely used in information security and refers to a service, which provides proof of the origin of data and the integrity of the data
Explanation:
Answer:
public static void swapPairs(int[] a){
int len=a.length;
if(len%2 ==0){
for(int i=0; i<len; i=i+2){
a[i]=a[i+1];
a[i+1]=a[i];
int[] b={a[i]+a[i+1]};
}
}
if(len%2 !=0){
for(int j=0; j<len; j=j+2){
a[j]=a[j+1];
a[j+1]=a[j];
a[len-1]=a[len-1];
int[] b={a[j]+a[j+1]+a[len-1]};
}
}
}
public static void printArray(int[] a){
System.out.println(a);
}
Answer:
Redundancy is the mechanism that occurs in database's data as the same data is stores in the multiple location.It creates repeated data by accident or for backup purpose.
The issues that arise due to the redundancy of the data is the storage space in database gets consumed and thus wastes the space in storing information in multiple locations.When any update occurs in the stored data's field value , it also has to be changed in the multiples occurrences.
Answer:
def main():
# Accept data from the user
n=int(input('Enter the value of n:'))
k=2;
sum=0
print('The list of the prime numbers are as follows:')
# This loop runs from k to n
while k<=n:
# Call is_prime() method,
# to check whether k is a prime or not
sum=sum+is_prime(k)
k=k+1
print('Sum of the prime numbers:',sum)
# is_prime() Method
def is_prime(k):
prime=0
i=1
# Check k is a prime or not
while i<=int(k):
# Find the factors of k
if (k % i) == 0:
prime=prime+1
i=i+1
# If k as two factors
if(prime==2):
print(k)
return k;
# If k as more than two factors
else:
return 0;
# Call the main() method
main()
Explanation:
