Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer:
The factors that affect self confidence are not having enough faith in yourself and letting what others say about you put you down
Explanation:
Plz mark brainlest it will help me so much
Space — each pressing of the key will be displayed as ·
Non-breaking space (°) is a space character that prevents an automatic line break at its position.
Answer:
C
data converted from double to integer.
The Rearrangement of the words are:
- Ear map
- Rent cup
- METREON
- Sister or
- Sister Cane
<h3>What is arrangement of words?</h3>
A sorting method is known to be the orders of entries that are based on each word or phrase found in a heading, e.g. spaces, etc.
The Rearrangement of the words are:
- Ear map
- Rent cup
- METREON
- Sister or
- Sister Cane
Learn more about Arrangement from
brainly.com/question/984329
#SPJ1
