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Arada [10]
3 years ago
10

.... . .-.. .-.. --- .-.-.- TRANSLATE THAT.

Computers and Technology
1 answer:
Mars2501 [29]3 years ago
3 0
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Create a recursive method, a method that calls itself, that returns the number of vowels that appear in any string given. Keep i
kvv77 [185]
<h2>Answer:</h2>

//Define the method as noOfVowels

   //Let it receive the string to be checked as argument

   public static int noOfVowels(String string){

   

       //Check the length of the string

       

       //If it is less than 1, then it is an empty string

       //Hence return 0

       if(string.length() < 1){    

           return 0;

       }

       

       //Else,

       else{

           //get the character at the first position in the string

           //and convert it to a lower case

           char x = string.toLowerCase().charAt(0);

           //Check if the character is a vowel

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               //if it is a vowel, add 1 to a recall of the method.

               //But this time, call the method with  

               //the string excluding the first character.

               //i.e the substring of the string starting at index 1 rather than 0

               return 1 + noOfVowels(string.substring(1));

           }

           

           else {

               //If it is not a vowel, just recall the method with

               //the string excluding the first character

               //i.e the substring of the string starting at index 1 rather than 0

               return noOfVowels(string.substring(1));

           }

       }

   }

   

<h2>Explanation:</h2><h2></h2>

The code has been written in Java and it contains comments explaining every part of the code. Please go through the comments carefully.

The actual lines of code have been written in bold face to distinguish them from comments.

The code is re-written without comments as follows;

   public static int noOfVowels(String string){

   

       if(string.length() < 1){    

           return 0;

       }

       

       else{

           char x = string.toLowerCase().charAt(0);

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               return 1 + noOfVowels(string.substring(1));

           }

           

           else{

               return noOfVowels(string.substring(1));

           }

       }

   }

   

3 0
3 years ago
What is a guardian node summary for theta staking tool
Diano4ka-milaya [45]

Answer: Theta Guardian

Explanation:

THETA is used to stake as a Validator or Guardian node, contributing to block production and the protocol governance of the Theta Network. By staking and running a node, users will earn a proportional amount of the new TFUEL generated. Relayers earn TFUEL for every video stream they relay to other users on the network.

3 0
2 years ago
An intruder with malicious intent breaks into an office and steals a hard drive
kakasveta [241]

Answer: data security

Explanation:

The company's authentication protocols and data encryption measures denotes data security.

Data security simply means protecting unauthorized people from having access to a particular data. This is done to prevent unauthorized access of important information or to prevent fraud. Some of the data security measures include data encryption, tokenization, hashing, etc.

4 0
3 years ago
Did the Z3 computer invented by Konrad Zuse have a negative effect on society?
musickatia [10]

Answer:

Explanation:

Không

4 0
2 years ago
Read 2 more answers
Write a program in C++ to implement bubblesort using the swap function ?
marishachu [46]

C++ program for implementation of Bubble sort  

#include <bits/stdc++.h>  

using namespace std;  

 void swap(int *x, int *y)  /*Defining Swap function of void return type*/

{  

  int temp = *x;  //Swaping the values  

   *x = *y;  

   *y = temp;  

}  

void bubbleSort(int array[], int n) /*Defining function to implement bubbleSort  */

{  

  int i, j;  

  for (i = 0; i < n-1; i++)      

      for (j = 0; j < n-i-1; j++)  /*The last i components are already in location  */

      if (array[j] > array[j+1])  

          swap(&array[j], &array[j+1]);  //Calling swap function

}  

int main()  //driver function

{  

   int array[] = {3, 16, 7, 2, 56, 67, 8}; //Input array  

   int n = sizeof(array)/sizeof(array[0]);  //Finding size of array

   bubbleSort(array, n); //Function calling  

   cout<<"Sorted array: \n";  

   for (int i = 0; i < n; i++)  //printing the sorted array

       cout << array[i] << " ";  

   cout << endl;  

 return 0;  

}  

<u>Output</u>

Sorted array:  

2 3 7 8 16 56 67

3 0
3 years ago
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