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3 years ago

Plz help me toofree ill give u what u want

Mathematics

2 answers:

Orlov [11]3 years ago

8 0

Answer:

Why do I want to say 70395?

I am not sure, I haven't done this stuff in a while

kondaur [170]3 years ago

4 0

Surface area = 2(19 x 15) + 2(15 x 13) + 2(13 x 19)
Surface area = 570 + 390 + 494
Surface area = 1454 cm²

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Answer: Surface area = 1454 cm²
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one bag of toy animals weigh12 ounces. what is the total weight, in ounces, of the bags of toy animals in one crate

LUCKY_DIMON [66]

Assuming I understand what you're saying, if there are 2 boxes in a crate and 18 bags in a box, the answer would be 12 * 36 = 432

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3 years ago

A triangle with area 45 square inches has a height that is two less than four times the width. Find the width and height of the

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

45 = (b(4b - 2))/2

90 = 4b2 - 2b

4b2 - 2b - 90 = 0

(2b + 9)(2b - 10) = 0

2b + 9 = 0

2b = -9

b = -9/2

If we were looking for zeroes, this would be an answer, but since we're looking for measurement, we don't use negative numbers.

90 = 4b2 - 2b

4b2 - 2b - 90 = 0

(2b + 9)(2b - 10) = 0

2b + 9 = 0

2b = -9

b = -9/2

7 0

3 years ago

Read 2 more answers

Can you guys help with me

Anika [276]

Answer:

x=8

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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3 years ago

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diamong [38]

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