Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Y=-2
You combine like terms which would be -14 and 22. 22-14=8. Then you subtract that from 0. 0-8=-8. Then divide -8 by 4y. -8÷4=-2
Function would be f(x) = 5x+85
here, x= 15
5(15)+85 = 75+85 = $160
Answer:
<h2>MP ≈ 2.98 cm</h2>
Step-by-step explanation:
Use sine:
We have:
Substitute:
<em>cross multiply</em>
<em>divide both sides by 1,000</em>
