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mart [117]
4 years ago
14

Databases can have various objects some of which are tables, queries, forms or views, and reports objects. Each of these has fie

lds or columns. Describe the function of each of these objects and how fields or columns differ from one object to another. Describe the different relationships that exist between tables, and provide real-world examples of how each of these might be used.
Computers and Technology
1 answer:
baherus [9]4 years ago
8 0

Answer:

Databases can have various objects some of which are tables, queries, forms or views, and reports objects. Each of these has fields or columns. Describe the function of each of these objects and how fields or columns differ from one object to another.

--

Database Objects provide a number of advantages, including database independence, automatic connection handling, declarative referential integrity, multi-level validations, security, and much more.

By using Database Objects in your application, you can take advantage of all of these capabilities without writing additional code.

Using database objects allows an application to avoid embedded SQL and it's maintenance difficulties and system dependencies. Applications simply interact with other Java objects, allowing the design of a system to be entirely object-oriented.

Database objects are built from the ground up to be database independent - they do not rely on the features of a specific underlying database to provide their functionality. This allows an application build using database objects to be ported from one database platform to another in literally moments, providing the potential for great scalability.

Describe the different relationships that exist between tables, and provide real-world examples of how each of these might be used.

-- relationship between tables can be foreign keys which are joined by various types of joins

A foreign key consists of one or more columns in a table whose value in one row uniquely identifies another row in the same or another table.

There are three types of relationships:

One-to-one: Both tables can have only one record on either side of the relationship. Each primary key value relates to only one (or no) record in the related table. They're like spouses%u2014you may or may not be married, but if you are, both you and your spouse have only one spouse. Most one-to-one relationships are forced by business rules and don't flow naturally from the data. In the absence of such a rule, you can usually combine both tables into one table without breaking any normalization rules.

One-to-many: The primary key table contains only one record that relates to none, one, or many records in the related table. This relationship is similar to the one between you and a parent. You have only one mother, but your mother may have several children.

Many-to-many: Each record in both tables can relate to any number of records (or no records) in the other table. For instance, if you have several siblings, so do your siblings (have many siblings). Many-to-many relationships require a third table, known as an associate or linking table, because relational systems can't directly accommodate the relationship.

Explanation:

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Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and
Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0
3 years ago
Point mode allows you to select cells for use in a formula by using your finger or the pointer
Serga [27]
That statement is true

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7 0
3 years ago
Modify an array's elements Write a for loop that iterates from 1 to numberSamples to double any element's value in dataSamples t
ValentinkaMS [17]

Answer:

See explaination for program code

Explanation:

%save as AdjustMinValue.m

%Matlab function that takes three arguments

%called number of samples count, user samples

%and min vlaue and then returns a data samples

%that contains values which are double of usersamples

%that less than min vlaue

%

function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)

dataSamples=userSamples;

%for loop

for i=1:numberSamples

%checking if dataSamples value at index,i

%is less than minValue

if dataSamples(i)<minValue

%set double of dataSamples value

dataSamples(i)= 2*dataSamples(i);

end

end

end

Sample output:

Note:

File name and calling method name must be same

--> AdjustMinValue(4, [2,12,9,20],10)

ans =

4 12 18 20

3 0
3 years ago
Which toolbar is located next to the office button and contain the commonly used commands​
Andrei [34K]

Answer: Quick Access Toolbar

The Quick Access Toolbar is located to the right of the Microsoft Office Button . It contains commands that are used most often, for example Redo, Undo and Save.

Explanation:

7 0
3 years ago
Why a design that doesn't fail initially fails after some time/use? identify at least 3 such mechanisms?
alina1380 [7]
Runs out of memory
has uninitialized    variables
uses  undefined behaviour

4 0
3 years ago
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