Network topology is the arrangement of the elements of a communication network. Network topology can be used to define or describe the arrangement of various types of telecommunication networks, including command and control radio networks, industrial fieldbusses and computer networks.
Advantages:
It is easy to handle and implement.
It is best suited for small networks.
Disadvantages:
The cable length is limited. This limits the number of stations that can be connected.
This network topology can perform well only for a limited number of nodes.
From what i learned from school, have a theme for the presentation and only have 1-3 pictures per slide that aren’t too big but small enough so you can read and see, also pictures that are self explanatory
Answer:
public class print{
public static void fillArray(int[] arr, int initialValue){
int n = arr.length;
for(int i=0;i<n;i++){
arr[i] = initialValue++;
}
for(int i=0;i<n;i++){
System.out.print(arr[i]+" ");
}
}
public static void main(String []args){
int[] array = new int[5];
int initialValue =3;
fillArray(array,initialValue);
}
}
Explanation:
Create the function with two parameter first is array and second is integer.
Then, declare the variable and store the size of array.
Take the for and fill the array from the incremented value of initialValue by 1 at every run of loop.
After loop, print the element of the array.
Create the main function which is used for calling the function and also declare the array with size 5 and initialValue with 3. After that, call the function with this argument.
Answer:
The image of truth table is attached.
Explanation:
In the truth table there is a separate table for the expression (A+B).C and for the expression (A.C)+(B.C) you can see in the truth table that the columns of (A+B).C is having same values as the (A.C)+(B.C).Hence we can conclude that (A+B).C is equal to (A.C)+(B.C).
REM PROGRAM TO DISPLAY AVERAGE OF TWO NUMBERS
CLS
INPUT “ENTER FIRST NUMBER”; A
INPUT “ENTER SECOND NUMBER”; B
INPUT “ENTER THIRD NUMBER”; C
AV = (A + B + C) / 3
PRINT “AVERAGE OF THREE NUMBERS”; AV
END
hope this helpz
