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3 years ago

Is 1/9 equal to 2/18

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Yes because if you simified 2/18 you get 1/9

UkoKoshka [18]3 years ago

4 0

Yes because you can add 1/9 and 1/9 to get 2/18

You might be interested in

Is 30 x 10 to the 4th power equal 3,000,000

garri49 [273]

It is not because 30×10^4 is 300,000.
The answer would then be...
30×10^5
Hope this helps!

7 0

3 years ago

How would I solve 16x^4-41x^2+25=0 ???

sveticcg [70]

$16{ x }^{ 4 }-41{ x }^{ 2 }+25=0$

${ x }^{ 4 }={ ({ x }^{ 2 }) }^{ 2 }\\ \\ 16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0$

First of all to make our equation simpler, we'll equal $x^{2}$ to a variable like 'a'.

So,

${ x }^{ 2 }=a$

Now let's plug $x^{2}$ 's value (a) into the equation.

$16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0\\ \\ { x }^{ 2 }=a\\ \\ 16{ (a) }^{ 2 }-41{ a }+25=0$

Now we turned our equation into a quadratic equation.

(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (fourth-degree equation) )

Let's solve for a.

The formula used to solve quadratic equations ;

$\frac { -b\pm \sqrt { { b }^{ 2 }-4\cdot t\cdot c } }{ 2\cdot t }$

The formula is used in an equation formed like this :

$t{ x }^{ 2 }+bx+c=0$

In our equation,

t=16 , b=-41 and c=25

Let's plug the values in the formula to solve.

$t=16\quad b=-41\quad c=25\\ \\ \frac { -(-41)\pm \sqrt { -(41)^{ 2 }-4\cdot 16\cdot 25 } }{ 2\cdot 16 } \\ \\ \frac { 41\pm \sqrt { 1681-1600 } }{ 32 } \\ \\ \frac { 41\pm \sqrt { 81 } }{ 32 } \\ \\ \frac { 41\pm 9 }{ 32 }$

So the solution set :

$\frac { 41+9 }{ 32 } =\frac { 50 }{ 32 } \\ \\ \frac { 41-9 }{ 32 } =\frac { 32 }{ 32 } =1\\ \\ a\quad =\quad \left\{ \frac { 50 }{ 32 } ,\quad 1 \right\}$

We found a's value.

Remember,

${ x }^{ 2 }=a$

So after we found a's solution set, that means.

${ x }^{ 2 }=\frac { 50 }{ 32 }$

and

${ x }^{ 2 }=1$

We'll also solve this equations to find x's solution set :)

${ x }^{ 2 }=\frac { 50 }{ 32 } \\ \\ \frac { 50 }{ 32 } =\frac { 25 }{ 16 } \\ \\ { x }^{ 2 }=\frac { 25 }{ 16 } \\ \\ \sqrt { { x }^{ 2 } } =\sqrt { \frac { 25 }{ 16 } } \\ \\ x=\quad \pm \frac { 5 }{ 4 }$

${ x }^{ 2 }=1\\ \\ \sqrt { { x }^{ 2 } } =\sqrt { 1 } \\ \\ x=\quad \pm 1$

So the values x has are :

$\frac { 5 }{ 4 }$ , $-\frac { 5 }{ 4 }$ , $1$ and $-1$

Solution set :

$x=\quad \left\{ \frac { 5 }{ 4 } \quad ,\quad -\frac { 5 }{ 4 } \quad ,\quad 1\quad ,\quad -1 \right\}$

I hope this was clear enough. If not please ask :)

3 0

3 years ago

Read 2 more answers

Is true or false 18= 18.00

larisa86 [58]

Answer:

it is true. any whole number has a 0 following the decimal

4 0

3 years ago

How many months old is Paula? if anyone really knows pls answer truthfull

sergiy2304 [10]

Answer:

I cant just answer that. I need numbers. and problems.

Step-by-step explanation:

6 0

3 years ago

The value of almost everything you own (assets), such as a car, computer, or house, depreciates (goes down) over time. when an a

Hoochie [10]

The final value of the truck after depreciation and the number of years you own the truck are the two variables in this problem.

The dependent variable is the final value of truck after depreciation and the independent variable is the number of years you own the truck.

We are given that the initial value of truck is $12,400 and depreciation value per year is $820.

We know that,

Final Value = Initial Value - Depreciation value per year * Number of years

Let Final value be y

Let the number of years be x.

Hence, the equation will be:-

y = 12400 - 820*x

y = 12400-820x

We can clearly see from the equation that the final value of truck will depend on the number of years you own the truck.

To learn more about depreciation, here:-

brainly.com/question/14682335

#SPJ4

6 0

2 years ago